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Eddi Din [679]
3 years ago
12

How can I solve the radical equation

Mathematics
1 answer:
lubasha [3.4K]3 years ago
7 0
I attached a picture, see if you can see what I'm doing. Basically, I start by squaring everything to get rid of the radical, but just remember at the end to always, always check your answers, because squaring your answers could get rid of some negative numbers that could result in imaginary answers. The answer I came up with was a=5,-2

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solve the system of equations 9x-9y=-9 and 4x-3y=-8 by combining the equations PLEASE HELP QUICKLY!!!!!
Len [333]

9x-9y=-9

x-y=-9/9

x-y+1=0.......(1)

4x-3y=-8

4x-3y+8=0....(2)

combining equation we get

(x-y+1)(4x-3y+8)=0

x(4x-3y+8)-y(4x-3y+8)+4x-3y+8=0

4x²-3xy+8x-4xy+3y²-8y+4x-3y+8=0

<u>4x²+3y²-7xy+12x-11y+8=0</u><u> </u><u>is</u><u> </u><u>your</u><u> </u><u>equation</u><u>.</u>

8 0
3 years ago
Read 2 more answers
I draw five cards from a randomly shuffled deck. What is the probability that those five cards are in either ascending or descen
Viefleur [7K]

Answer: The probability of drawing 5 cards in either ascending or descending order out of the deck of 52 standard playing cards is 0.84%.

Step-by-step explanation: We have the following cards in a deck: 1(ace), 2, 3, 4, 5, 6, 7, 8, 9, 10, 12(Jack), 13(Queen), 14(King) (thirteen different in total). There are 4 copies of each of them yielding 52 cards in total. First to draw all of the cards in the ascending order all of the drawn cards need to be different. Imagine you have 13 piles of 4 identical cards. Let us calculate the number of ways you can select 5 different ones (the order matters). First you select 5 different piles (this secures that each card is different) and this is possible to do in \frac{13!}{(13-5)!} (we use the formula for variations since the order matters). Now, each card in the pile can be selected in 4 different ways so the total number of sequences with 5 different cards is 4^5\frac{13!}{(13-5)!}. Now we select out of these sequences the clases of those that contain exactly the same cards but in different order. Only 4 of the sequences within the same class will be in ascending order out of 4*5! which is the total number of the sequences within the class! This means that we have to multiply our total number of sequences of 5 different cards by \frac{4}{4\cdot 5!}=\frac{1}{5!} and this yields the final answer of total number of ascending sequences to be

4^5\frac{13!}{(13-5)!5!}.  

The total number of possible ways to draw 5 out of 52 cards is just

\frac{52!}{(52-5)!}.

This yields for the probability

\frac{4^5\frac{13!}{(13-5)!5!}}{\frac{52!}{(52-5)!}}=0.42\%

Exactly the same calculation applies for the descending order. So the probabilty of the cards being in either ascending or descending order is just the sum of these two (the events are mutually exclusive, you cannot have both the ascending and descending order at the same time) yielding the final probability of 0.84\%.

6 0
3 years ago
PLs hElP gIvInG DUE TODAY 23 points
taurus [48]

Answer:

Answer down below!

Step-by-step explanation:

1) 10

2) 4

3) 6

----------------

1 ) we know that perimeter = all the sides combined.

  • 12+12+10+10=44
  • (44 is the given perim.; so therefore if 12x2+10x2=44, 20 is the missing width.

2 ) we know that area = lw.

  • 10x4= 40
  • 44 is the given area, so therefore if 10x4=40, 4 is the base.

3 ) we know that area = lw.

we need to find the area of the square. 3 x 2 = 6. 6 is the area of the missing square or the part that needs to be covered.

4 0
2 years ago
Point (-5,2) is reflected over the y axis. Where is the new point located?
umka21 [38]
The new point is (5,2)
8 0
4 years ago
Which would be the correct answer ?
lara31 [8.8K]
Its not A and its not D. Its B or C. I think its C. 
I hope this helped.
8 0
3 years ago
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