3 years ago

How can I solve the radical equation

1 answer:

7 0

I attached a picture, see if you can see what I'm doing. Basically, I start by squaring everything to get rid of the radical, but just remember at the end to always, always check your answers, because squaring your answers could get rid of some negative numbers that could result in imaginary answers. The answer I came up with was a=5,-2

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Step-by-step explanation:

$x = y + 8.....(1) \\ \\ x = 5y + 12....(2) \\ \\ from \: equations \: (1) \: and \: (2) \\ \\ 5y + 12 = y + 8 \\ \\ 5y - y = 8 - 12 \\ \\ 4y = - 4 \\ \\ y = \frac{ - 4}{4} \\ \\ y = - 1 \\ \\ plug \: y = - 1 \: in \: equation \: (1) \\ \\ x = - 1 + 8 \\ \\ x = 7 \\ \\ (x, \: y) = (7, \: - 1)$