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schepotkina [342]

2 years ago

8

The black line is a graph of y=x. Which of these equations could represent the blue line

1 answer:

Ymorist [56]2 years ago

6 0

Answer:

third option

Step-by-step explanation:

y = 1/2 x

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5 0

2 years ago

What is the value in meters per second squared of the acceleration of gravity?

Lady bird [3.3K]

In real-life physics, acceleration due to gravity will change respect to altitude. Check out the attached image (source: Wikipedia).

However, in high-school physics, acceleration due to gravity is represented by the letter g, which has a value of 9.81 meters per second squared.

This means that an object being dropped straight down will be moving 9.81 meters per second faster than it was 1 second ago. I hope this helps! :)

7 0

2 years ago

Need some help on this math question.

melamori03 [73]

Answer:

4x cm.

Step-by-step explanation:

Suares have to have all 4 sides equal. The area of the rectangle (2x8) is 16.

16/4 = 4, so the square has sides of 4cm each to equal an are of 16. (4x4=16)

4 0

2 years ago

Let f be a function. Use each statement to find the coordinates of a point on the graph of f. f (5) = 9

omeli [17]

Answer:

400

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

2 years ago