Question

What are the zeros of f(x) = x2 + x - 12?

Answer 1

Answer:

(x+4)(x-3) or A

Step-by-step explanation:

I'm going to assume that you meant to write x² and not x2

which means we have

x²+x-12

and we need to factor this

to do this we need two numbers that add up to 1 (b) but mulitply to -12 (a*c)

our two numbers are

4, -3

Which means the answer is

(x+4)(x-3)

Answer 2

${ \large{ \bf{f(x) = x {}^{2} + x - 12}}}$

${ \large{ \bf{zeros = \dfrac{ - b± \sqrt{b {}^{2} - 4ac } }{2a} }}}$

${ \large{ \bf{zeros = \dfrac{ - 1± \sqrt{1 {}^{} + 48 } }{2} }}}$

${ \large{ \bf{zeros = \dfrac{ -1± 7 }{2} }}}$

${ \large{ \bf{➢ \: \: zeros = - 4 \: \: and \: 3 }}} \: \: \: \: \: \: (ans)$

Opt A.) is the answer