Question

Can somebody help me please ​

Answer 1

9514 1404 393

Answer:

• 3n+6 (n = smallest)
• 3n (n = middle)

Step-by-step explanation:

The usual method for doing this is to let n represent the smallest one. Then the three integers are ...

  n, n+2, and n+4

and their sum is ...

  (n) +(n+2) +(n+4) = 3n+6 . . . . sum of 3 consecutive odd integers (n = smallest)

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Personally, for consecutive number problems, I prefer to let the variable represent the average value. If n is the average value of 3 consecutive odd integers, is is the middle integer. Of course, the sum will be 3 times the average:

  (n-2) +(n) +(n+2) = 3n . . . . sum of 3 consecutive odd integers (n = middle one)