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Komok [63]
2 years ago
8

The ratio of boys to girls is 14:17 if there are a total of 7626 students how many boys and how many girls are there ?

Mathematics
2 answers:
natima [27]2 years ago
8 0

Answer: boys = 3444 , girls = 4182

3444:4182

Step-by-step explanation:

14(246)= 3444

17(4182)= 4182

4182+3444= 7626

Finger [1]2 years ago
6 0

Answer: 3444 boys, 4182 girls

Let there be 14x boys and 17x girls. Then there are 31x total students. Since 31x = 7626, x = 246. Then there are 14(246) = 3444 boys and 17(246) = 4182 girls.

i hope this was helpful! :D

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statuscvo [17]
1a. It is because each x only has 1 y and it has an equation
1b. It is not a function because each x has more than 1 y.
1c. It is not a function because there can be no equation written for this graph.
7 0
3 years ago
The perimeter of a rectangle is greater than or equal to 74 meters.
Ksju [112]

Answer:

12

Step-by-step explanation:

First, multiply the length by two then, subtract the total by the sum, last divide by two.

(25 * 2)

(74 - 50)

(24/2)

Answer = 12

5 0
3 years ago
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Please help, thanks! Ok so, you pick a card at random, put it back, and then pick another card at random. There are FIVE cards a
tatyana61 [14]

Answer:

P(x > 1\ and\ x < 2) = \frac{4}{25}

Step-by-step explanation:

Given

S = \{1,2,3,4,5\}

n(S) = 5

Required

P(x > 1\ and\ x < 2)

P(x > 1\ and\ x < 2) is calculated as:

P(x > 1\ and\ x < 2) = P(x > 1) * P(x < 2)

Since it is a probability with replacement, we have:

P(x > 1\ and\ x < 2) = \frac{n(x > 1)}{n(S)} * \frac{n(x < 2)}{n(S)}

For x > 1, we have:

x > 1 = \{2,3,4,5\}\\

n(x > 1) = 4

For x < 2, we have:

x < 2 = \{1\}

n(x < 2) = 1

P(x > 1\ and\ x < 2) = \frac{n(x > 1)}{n(S)} * \frac{n(x < 2)}{n(S)}

becomes

P(x > 1\ and\ x < 2) = \frac{4}{5} * \frac{1}{5}

P(x > 1\ and\ x < 2) = \frac{4}{25}

6 0
3 years ago
What is equivalent ratio of 5:8:4 and explain how u got it
igor_vitrenko [27]

this is example

So, first we need to write the given ratio as fraction,

= 8/18

= (8 × 2)/(18 × 2)

= 16/36

= 16 : 36 (one equivalent ratio),

So, 16 : 36 is an equivalent ratio of 8 : 18.

Now we will find another equivalent ratio of 8 : 18 by using division.

Similarly, first we need to write the given ratio as fraction,

= 8/18

= (8 ÷ 2)/(18 ÷ 2)

= 4/9

= 4 : 9 (another equivalent ratio)

So, 4 : 9 is an equivalent ratio of 8 : 18.

Therefore, the two equivalent ratios of 8 : 18 are 16 : 36 and 4 : 9.

2. Frame two equivalent ratios of 4 : 5.

Solution:

To find two equivalent ratios of 4 : 5 we need to apply multiplication method only to get the answer in integer form.

First we need to write the given ratio as fraction,

= 4/5

= (4 × 2)/(5 × 2)

= 8/10

= 8 : 10 is one equivalent ratio,

Similarly again, we need to write the given ratio 4 : 5 as fraction to get another equivalent ratio;

= 4/5

= (4 × 3)/(5 × 3)

= 12/15 is another equivalent ratio

Therefore, the two equivalent ratios of 4 : 5 are 8 : 10 and 12 : 15.

Note: In this question we can’t apply division method to get the answer in integer form because the G.C.F. of 4 and 5 is 1. That means, 4 and 5 cannot be divisible by any other number except 1.

6 0
3 years ago
What is the complete factorization of the polynomial function over the set of complex numbers? f(x)=x^3+3x^2+16x+48
Tamiku [17]

Answer:(x+3)(x+4i)(x-4i)  is the required factorization of f(x).


Step-by-step explanation:

To factor the expression we must first group the terms and then take out common from these groups

f(x)=x^3+3x^2+16x+48=(x^3+3x^2)+(16x+48)

Taking x^2 common from first group and the 16 from second group we get:


f(x) = x^2(x+3)+16(x+3) = (x+3)(x^2+16)


Now, to factor in complex from we have to break term x^2+16


f(x)= (x+3){x^2-(-4i)^2}

As, i^2 = -1 , therefore (-4i)^2 = 16i^2 =-16

Also using identity a^2-b^2 =(a+b)(a-b)

On solving

f(x) = (x+3)(x+4i)(x-4i)

(x+3)(x+4i)(x-4i)  is the required factorization of f(x).


8 0
3 years ago
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