Answer:
Direct proportional graphs <u>do not</u> need to start from the origin.
Step-by-step explanation:
Direct proportional graphs do not need to start from the origin. However, <u><em>all </em></u>direct proportional graphs <u>must</u><u> </u><u>go through</u> the origin.
Regardless of the value of the <u>constant of proportionality</u>, <em>k</em>, the graph of the lines all go through the point of origin, (0, 0).
As a proof, the attached screenshot shows the graph of three equations of direct variations. The graphed direct variation equations, y = 2x, y = -2x, and y = ¼x all <u>go through the point of origin.</u>
Answer:
Step-by-step explanation:
Zeros = 5 & 6
Let the variable of the quadratic function be x
Therefore, (x - 5) & (x-6) are factors

Answer:
(the statement does not appear to be true)
Step-by-step explanation:
I don't think the statement is true, but you CAN compute the intercepted arc from the angle.
Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.
Therefore, adding the angles together, we have:
alpha + 90 + 90 + <FDG = 360
Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)
Answer:
The sigma notation would look like this:
∞
Σ 48(1/4)^i-1
i = 1
Step-by-step explanation:
I can't seem to find a good way to make it more connected so I'll just have to tell you. The ∞ is above the ∑, while the i = 1 is under it. That is all one thing. The rest is followed as normal, and it is all next to the ∑
It’s c just try think of it logically