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3 years ago

100 POINTS FOR ANYONE WHO CAN ANSWER THESE! <3

Mathematics

1 answer:

faust18 [17]3 years ago

8 0

Answer:

∠1 = 142°

reason: angles 1 and 2 are supplementary so they equal 180. 180-38 is 142

∠3 = 38°

reason: angles 2 and 3 are adjacent angles because they are diagonal from each other so they will equal the same measure.

∠4 = 142°

reason: since angle 4 is adjacent to angle 1 and is supplementary to angle 3, it has to be 142

∠5 = 38°

reason: since it is a transversal that means both of the intersections are the same measurements. so angle 5 is 38 since it matches up with angle 2

∠6 = 142°

reason: for the same reason as angle 5. angle 6 matches up with angle 1 so it has to equal 142.

∠8 = 142°

reason: since angle 8 is adjacent to angle 6 it has to equal 142. angle 8 is also a transverse angle to angle 4. and since angle 4 also equals 142, 8 has to also

Step-by-step explanation:

hope this helped you :)

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Step-by-step explanation:

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3 years ago

Find the limit, if it exists. (If an answer does not exist, enter DNE.) lim (x, y) → (0, 0) x4 − 34y2 x2 + 17y2

HACTEHA [7]

Answer:

Step-by-step explanation:

Given the limit of the function $\lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}$ , to find the limit, the following steps must be taken.

Step 1: Substitute the limit at x = 0 and y = 0 into the function

$= \lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}\\= \frac{0^4-34(0)^2}{0^2+17(0)^2}\\= \frac{0}{0} (indeterminate)$

Step 2: Substitute y = mx int o the function and simplify

$= \lim_{(x,mx) \to (0,0)} \frac{x^4-34(mx)^2}{x^2+17(mx)^2}\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^4-34m^2x^2}{x^2+17m^2x^2}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2(x^2-34m^2)}{x^2(1+17m^2)}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2-34m^2}{1+17m^2}\\$

$= \frac{0^2-34m^2}{1+17m^2}\\\\= \frac{34m^2}{1+17m^2}\\\\$

Since there are still variable 'm' in the resulting function, this shows that the limit of the function does not exist, Hence, the function DNE

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