There are 8 times as many females as males on the maths course at university. What fraction of the course are female?
1 answer:
Answer:
Step-by-step explanation:
Let the males = x
Let the females = 8x
Let the total in the class = x + 8x = 9x
Females = 8x / 9x = 8/9
If you want the decimal, it is .889
You might be interested in
1) x=6, y=3
2) no solution
(21+39a)/20. Because they have to have the same denominator
Answer:
9+4]65%=4
Step-by-step explanation:
Answer:
y= -1/2x
Step-by-step explanation:
y-y1/x-x1=y2-y1/x2-x1
y-1/x+2=-1/2
2y-2= -x-2
2y= -x-2+2
2y=-x
y=-1x/2„
