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raketka [301]
3 years ago
10

It would be nice if anyone could help​

Mathematics
1 answer:
Allushta [10]3 years ago
5 0
<h3>Answer:  x = 140   (choice C)</h3>

========================================================

Explanation:

Focus on the upper semicircle. It's composed of the arc pieces that are 30 degrees, x degrees, and y degrees. The y is the missing unmarked portion of the upper semicircle.

Subtract the 30 and y degree angles, divide by 2, and set that result equal to 10. This will help us solve for y

(30-y)/2 = 10

30-y = 10*2

30-y = 20

-y = 20-30

-y = -10

y = 10

Because the 30, x and y arcs form a semicircle, this must mean the three arcs add to 180 degrees

30+x+y = 180

30+x+10 = 180

x+40 = 180

x = 180-40

x = 140

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kiara made a square baby blanket. She decided to add 1 foot of material to one side, then cut 4 inches of material off from an a
alexira [117]

Answer:

  • 784 in²

Step-by-step explanation:

Let the original side is x.

1 foot = 12 inches

<u>New sides of a rectangle are:</u>

  • x + 12 and x - 4

<u>The area of rectangle is:</u>

  • (x + 12)(x - 4) = 960

<u>Solve for x:</u>

  • x² + 8x - 48 = 960
  • x² + 2*4*x + 16 - 64 = 960
  • (x + 4)² = 1024
  • x + 4 = 32
  • x = 28

<u>Area of the original blanket:</u>

  • A = 28² = 784 in²
5 0
3 years ago
Hi, please help me out with this math problem.
GalinKa [24]

9514 1404 393

Answer:

  x - 4

Step-by-step explanation:

The expression simplifies to ...

  \sqrt{x^2-8x+16}=\sqrt{(x-4)^2}=|x-4|

For x ≥ 4, the argument of the absolute value function is non-negative, so it remains unchanged. The simplified expression is ...

  x - 4 . . . . for x ≥ 4

6 0
3 years ago
Solve this system of linear equations.
yuradex [85]
A) -2, -1
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3 years ago
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Sliva [168]
15. 22=4*5+2
16. 23=3+4*5
7 0
2 years ago
15.
boyakko [2]

Explanation:

a)

{3 \choose 2} = \frac{3!}{2!(3-2)!} = \frac{6}{2*1} = 3

{3 \choose 1} = \frac{3!}{1!(3-1)!} = \frac{6}{1*2} = 3

b) First, we have that

{n \choose k} = \frac{n!}{k!(n-k)!}

On the other hand,

{n \choose n-k} = \frac{n!}{(n-k)!(n(n-k))!} = \frac{n!}{(n-k)!k!}

Therefore, both expressions are equal. This makes sense, because selecting k elements from a group of n is the same than specify which elements you will not select. In order to specify those elements you need to select the n-k elements that will not be selected. Hence, each time you are selecting k from n, you are also selecting n-k from n, and from that reason both combinatorial numbers are equal.

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4 years ago
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