All categories

3 years ago

Help please :) I don't understand :)

Mathematics

1 answer:

snow_tiger [21]3 years ago

5 0

Answer:

I would try D. 13 for the first one and for the second one I would try D.14

You might be interested in

A square pyramid has base area 64 square centimeters. The surface area of this pyramid is 224 square centimeters. Find the heigh

dolphi86 [110]

Answer:

$h \approx 12.7\,cm$

Step-by-step explanation:

The side of the square base is:

$l = \sqrt{64\,cm^{2}}$

$l = 8\,cm$

The formula for the surface area of the pyramid is:

$A_{s} = \frac{1}{2}\cdot (3\cdot l)\cdot \sqrt{0.25\cdot l^{2}+h^{2}} + l^{2}$

The height is cleared in the previous expression:

$A_{s} - l^{2} = \frac{3}{2}\cdot l\cdot \sqrt{0.25\cdot l^{2}+h^{2}}$

$\frac{2}{3}\cdot \frac{A_{s}-l^{2}}{l} = \sqrt{0.25\cdot l^{2} + h^{2}}$

$\frac{4}{9}\cdot \left(\frac{A_{s}-l^{2}}{l} \right)^{2} = \frac{1}{4} \cdot l^{2} + h^{2}$

$h = \sqrt{\frac{4}{9}\cdot \left(\frac{A_{s}-l^{2}}{l} \right)^{2} - \frac{1}{4}\cdot l^{2}}$

$h = \sqrt{\frac{4}{9}\cdot \left[\frac{224\,cm^{2}-(8\,cm)^{2}}{8\,cm}\right]^{2}-\frac{1}{4}\cdot (8\,cm)^{2} }$

$h \approx 12.7\,cm$

6 0

3 years ago

3 out of 12 candies are orange in a bag of 100 about how many candies are orange

ankoles [38]

Answer:

the answer is 88

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Translate the sentence into an equation.

Marta_Voda [28]

Answer:

Step-by-step explanation:

7x + 6 = 3

If you want to continue to find the value of x, do this:

7x + 6 - 6 = 3 - 6 = -3, or

7x = -3, or

x = -3/7

4 0

3 years ago

Assume that a policyholder is four times more likely to file exactly two claims as to file exactly three claims. Assume also tha

kykrilka [37]

Answer:

1.3125

Step-by-step explanation:

Given that our random variable $X$ follows a Poisson distribution $P(X=k)=\frac{\lambda^k e^-^p}{k!} \ \ \ \ \ \ \ \ p=\lambda$

Evaluate the formula at $k=2,3:$

$P(X=2)=0.5\lambda^2e^{-\lambda}\\\\P(X=3)=\frac{1}{6}\lambda^2e^{-\lambda}$

#since

$4P(X=2)=P(X=3);\\\\0.5\lambda^2e^{-\lambda}=4\times\frac{1}{6}\lambda^3e^{-\lambda}\\\\0.5\lambda^2=\frac{2}{3}\lambda^3\\\\0.75=\lambda$

The mean and variance of the Poisson distributed random variable is equal to $\lambda$ :

$\mu=\lambda=0.75\\\sigma ^2=\lambda=0.75$

#By property variance:

$\sigma ^2=V(X)=E(X^2)-(E(X))^2=E(X^2)\\\\E(X^2)=\sigma^2+\mu^2=0.75+0.75^2=1.3125$

The expectation is 1.3125

4 0

4 years ago

Answer A and B

ArbitrLikvidat [17]

Answer:

A: 630 was the highest

B: camped at 380

7 0

2 years ago

Read 2 more answers