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3 years ago

10

Adalyn drove 12 miles from her home to her school and then drove back. Graph A shows her distance from home during the trip. Gra

ph B will show her distance from the school during the trip. Complete each statement about Graph B.

2 answers:

Luba_88 [7]3 years ago

8 0

Answer: 60 mph.

(486+316+638)/24

The distances given by the table. The time driven is 24 (given by the problem). So the average speed is simply the total distance divided by the time driven.

Step-by-step explanation:

Ad libitum [116K]3 years ago

6 0

Answer:

On Graph B, at 0 minutes, the height of the graph will be at 12 miles

Then, the graph will decrease until 15 minutes, when Adalyn reaches the school. At 15 minutes, the height of Graph B will be at 0 miles.

Step-by-step explanation:

Since she is coming back from school the numbers are decreasing.

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spayn [35]

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I wasn't sure if you wanted me to solve for x, but I did anyways.
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tatuchka [14]

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3 years ago

You have 8 gallons of lemonade to sell. You use cone-shaped cups that are 9 centimeters in diameter and 12 centimeters tall. Eac

andre [41]

You will need 119 cups to sell all of the lemonade.

Step-by-step explanation:

Given,

Diameter of cups = 9 cm

Radius of cup = $\frac{Diameter}{2}=\frac{9}{2}=4.5\ cm$

Height of cups = 12 cm

We will find volume of cup.

$Volume = \frac{1}{3}\pi r^2h\\$

Putting all the values

$Volume=\frac{1}{3}(3.14)(4.5)^2(12)\\\\Volume=\frac{1}{3}(3.14)(20.25)(12)\\\\Volume= \frac{763.02}{3}\\\\Volume= 254.34\ cm^3$

Therefore;

Each cup can hold 254.34 cubed centimeter of lemonade.

Number of gallons = 8

1 gallon = 3785 cm³

8 gallons = 3785*8 = 30280 cm³

Let,

x = Number of cups

Volume of lemonade in one cup * Number of cups = Volume of 8 gallons

254.34x=30280

Dividing both sides by 254.34

$\frac{254.34x}{254.34}=\frac{30280}{254.34}\\x=119.05$

Rounding off to nearest whole number

x = 119

You will need 119 cups to sell all of the lemonade.

Keywords: volume, division

Learn more about volume at:

#LearnwithBrainly

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3 years ago

If BTS=GHD BS=25 TS=14 BT=31 GD=4x-11 S=56 B=21 and H=(7y+5) find the values of x and y

77julia77 [94]

Given:

Consider the completer question is "If ∆BTS≅∆GHD, BS=25, TS=14, BT=31, GD=4x-11, m∠S=56, m∠B=21 and m∠H=(7y+5), find the values of x and y.

To find:

The values of x and y.

Solution:

We have,

$\Delta BTS\cong \Delta GHD$ (Given)

$BS=GD$ (CPCTC)

$25=4x-11$

$25+11=4x$

$36=4x$

Divide both sides by 4.

$9=x$

In ∆BTS,

$\angle B+\angle T+\angle S=180^\circ$ (Angle sum property)

$21^\circ+\angle T+56^\circ=180^\circ$

$77^\circ+\angle T=180^\circ$

$\angle T=180^\circ-77^\circ$

$\angle T=103^\circ$

Now,

$\angle T=\angle H$ (CPCTC)

$103=7y+5$

$103-5=7y$

$98=7y$

Divide both sides by 7.

$14=y$

Therefore, the value of x is 9 and value of y is 14.

3 0

3 years ago

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harina [27]

Answer:

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Step-by-step explanation:

If the two lines are parallel and has other line intersect ; the angle will be equal so the answer is 35.

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