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3 years ago

Please please help me asap

Mathematics

2 answers:

tia_tia [17]3 years ago

7 0

A, B, and C are correct.

qaws [65]3 years ago

5 0

The answer is A bc there is no decimal or what ever

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Jarred sells DVDs. His inventory shows that he has a total of 3,500 DVDs. He has 2,342 more contemporary titles than classic tit

Mamont248 [21]

Here, x - y = 2342
x = 2342 + y

Substitute this value into first equation,
2342 + y + y = 3500
2y = 3500 - 2342
y = 1158/2
y = 579

So, x = 2342 + 579 = 2921

In short, Your Answer would be 2921 contemporary titles

Hope this helps!

3 0

3 years ago

Read 2 more answers

What is the solution set

netineya [11]

The answer is c as -2 is -2/1 , -2/1 times 1/2 equals -1 which makes it so If x is -2 or less than it won’t exceed -1

4 0

3 years ago

Find the mean of the following: 158, 213, 107, 213, and 213. If needed, round your answer to the nearest tenth

Shalnov [3]

Answer:

180.8

Step-by-step explanation:

1. Add all the numbers

2. Divide the sum by 5

3. you get the answer

4 0

3 years ago

Read 2 more answers

Find the length of the leg of the right triangle leave your answer in simplest radical form

erastova [34]

Answer:

a =12*sqrt(2)

Step-by-step explanation:

3. The Pythagorean theorem states

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

a^2 +21^2 = 27^2

a^2 +441 =729

Subtract 441 from each side

a^2 +441-441 = 729 -441

a^2 =288

Take the square root of each side

sqrt(a^2) = sqrt(288)

sqrt(xy) = sqrt(x)sqrt(y)

a = sqrt(144)sqrt(2)

a =12*sqrt(2)

7 0

3 years ago

According to a study done by a university student, the probability a randomly selected individual will not cover his or her mou

VikaD [51]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(X = 8) = 0.0037$

$P(X < 5) = 0.805$

$P(X > 6) = 0.0206$

I would be surprised because the value is very small , less the 0.05

Step-by-step explanation:

From the question we are told that

The probability a randomly selected individual will not cover his or her mouth when sneezing is $p = 0.267$

Generally data collected from this study follows binomial distribution because the number of trials is finite , there are only two outcomes, (covering , and not covering mouth when sneezing ) , the trial are independent

Hence for a randomly selected variable X we have that

$X \ \ \~ \ \ { B ( p , n )}$

The probability distribution function for binomial distribution is

$P(X = x ) = ^nC_x * p^x * (1 -p) ^{n-x}$

Considering question a

Generally the the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when sneezing is mathematically represented as

$P(X = 8) = ^{12} C_8 * (0.267)^8 * (1- 0.267)^{12-8}$

Here C denotes combination

$P(X = 8) = 495 * 0.000025828 * 0.28867947$

$P(X = 8) = 0.0037$

Considering question b

Generally the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when sneezing is mathematically represented as

$P(X < 5 ) =[P(X = 0 ) + \cdots + P(X = 4)]$

=> $P(X < 5 ) =[ ^{12} C_0 * (0.267)^0 * (1- 0.267)^{12-0} + \cdots + ^{12} C_4 * (0.267)^4 * (1- 0.267)^{12-4} ]$

=> $P(X < 5 ) = 0.02406 + 0.10516 + 0.21067 + 0.25580 + 0.20964$

=> $P(X < 5) = 0.805$

Considering question c

Generally the probability that fewer than half(6) covered their mouth when sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as

$P(X > 6) = 1 - p(X \le 6)$

=> $P(X > 6) = 1 - [P(X = 0) + \cdots + P(X =6)]$

=> $P(X > 6)=1 - [^{12} C_0 * (0.267)^0 * (1- 0.267)^{12-0}+ \cdots + ^{12} C_4 * (0.267)^6 * (1- 0.267)^{12-6} ]$

=> $P(X > 6)= 1 - [0.02406 + \cdots + 0.0519 ]$

=> $P(X > 6) = 0.0206$

I would be surprised because the value is very small , less the 0.05

8 0

3 years ago