1.) 4(x+3)
Find the GCF, Greatest Common Factor, of 4x and 12.
4x=2*2*x
12=3*2*2
The greatest common factor is 4. Put this outside of the parentheses. (You would multiply the 2*2)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Solution: 4(x+3)
To check, distribute to see if it works.
4x+12
2.) 2(4r+7)
Find the GCF of 8r and 14
8r=2*2*2*r
14= -1*7*2
The greatest common factor is 2. (There is only 1 two, so you would not multiply them.)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Multiply the 2*2*r as one addend and the -1*7 as the other.
Solution: 2(4r-7)
To check, distribute to see if it works.
8r-14
Do you get it now?
3.) 5(x+7)
4.) 7(2x+1)
5.) Cannot be factored.
32x-15
Find the GCF of 32x and -15
32x: 2*2*2*2*2*x
-15: -1*5*3
Because there are no similar factors other than 1, it cannot be factored.
6.) 8(4x+3)
7.) 3(2x-3)
8.) 24(1x+2)
9.) 9(-2x+8)
10.) Cannot be factored
11.) 8(1x+3)
12.) 50(1x+5)
Answer:
$92.86
Step-by-step explanation:
Since it's AT LEAST 1800, the inequality sign would be ≥ 1800
Equation:
500 + 14x ≥ 1800
14x ≥ 1800 - 500
14x ≥ 1300
x ≥ 92.86
Answer:
I don't use Geogebra, but the following procedure should work.
Step-by-step explanation:
Construct a circle A with point B on the circumference.
- Use the POINT and SEGMENT TOOLS to create a circle with centre B and radius BA.
- Use the POINT tool to mark points D and E where the circles intersect.
- Use the SEGMENT tool to draw segments from C to D, C to E, and D to E.
You have just created equilateral ∆CDE inscribed in circle A.
Answer:
plz make brainy least and your answer is here