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masya89 [10]
3 years ago
11

Please help :(( fillerfillerfiller

Mathematics
1 answer:
snow_tiger [21]3 years ago
6 0

Answer:

1,385.442360233099

Step-by-step explanation:

Pie times the radius squared

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The answer is most likely 32 I’m the best at math
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3 years ago
Ben wants to estimate the cost of dinner and a movie for himself and his friend. He knows the following information
Kamila [148]

Answer:

B. $3100

Step-by-step explanation:

if he's going to pay for his friend. The least expensive dinner menu is $725, for him and his friend it would be $1450. Then for the movie tickets it's $8.00 each, $16.00. $1450+$16.00=$30.50. Round that to the closest whole number, $3100.

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4 years ago
Which expression is equivalent to the one in the picture?
Ne4ueva [31]

Answer:

d.

Step-by-step explanation:

To convert a root to a fraction in the exponent, remember this rule:

\sqrt[n]{a^{m}}=a^{\frac{m}{n}}

The index becomes the denominator in the fraction. (The index is the little number in front of the root, "n".) The original exponent remains in the numerator.

In this question, the index is 4.

The index is applied to every base in the equation under the root. The bases are 16, 'x' and 'y'.

\sqrt[4]{16x^{15}y^{17}} = (\sqrt[4]{16})(\sqrt[4]{x^{15}})(\sqrt[4]{y^{17}}) = (2)(x^{\frac{15}{4}}})(y^{\frac{17}{4}}) = 2x^{\frac{15}{4}}}y^{\frac{17}{4}}

To find the quad root of 16, input this into your calculator. Since 2⁴ = 16, \sqrt[4]{16} = 2.

For the "x" and "y" bases, use the rule for converting roots to exponent fractions. The index, 4, becomes the denominator in each fraction.

2x^{\frac{15}{4}}y^{\frac{17}{4}}

5 0
4 years ago
Question 4 of 25
soldi70 [24.7K]

Answer:

D)graph c

Step-by-step explanation:

it's my opinion do not take it as important

7 0
2 years ago
Write and solve an inequality for the following sentence: Jan has saved $50 in her saving account and needs to save at least $26
Juliette [100K]

50 + x ≥ 268

X ≥ 218

STEP BY STEP WORK

50 + x ≥268
-50 -50

x ≥218

Jan needs to save at least $218 for camp


Hope I helped :)
8 0
3 years ago
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