Answer:
(y^2)/4 square meters
Step-by-step explanation:
For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.
If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...
(x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2
That is, the difference in area between the square and the rectangle is ...
(x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4
The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.
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Answer:
Since we have the information for Angles 1 and 3, and they are vertical, we can set them equal to each other. Once we have done this we can find the measures of them combined, and subtract it from 360 in order to only have the measure of 2 and its vertical angle. Finally, all we need to do now is divide the remaining measure by 2, and this will give us the measure of angle 2.
Angle 1=Angle 3
4x+30=2x+48
2x+30=48
2x=18
x=9
Angle 1=4(9)+30
Angle 1=36+30
Angle 1=66
Angle 1=Angle 3
Angle 1+ Angle 3=132
360-132=228
228/2=114
Angle 2= 114
Answer:
35÷7=5
Step-by-step explanation:
we have 7 small boxes in an oval and there are 5 ovals
All the boxes add up to 35
We can represent the base as z and the height as 2z+6. We are going to use the formula A=1/2*b*h and solve for z
180=1/2*z*(2z+6)
360=2z^2+6z
0=2z^2+6z-360
0=2(z^2+3z-180)
0=(z+15)(z-12)
So z=-15 and 12 but it must be positive so then the base is equal to 12
When we plug this into 2z+6 we get 30 for the height
2(12)+6=30
Hope this helps
