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zavuch27 [327]
3 years ago
11

Arniez car ussd 100 cup of gasoline during a drive he paid $3.12 per gallon for gas how much did the gas cost please show work

Mathematics
2 answers:
german3 years ago
4 0
Since Arniez used 100 cups of gasoline and had to pay $3.12 per gallon it would be
100 x 312 which is $31,200
ehidna [41]3 years ago
4 0
100 cups = 6.25 gallons
6.25 ÷ 3.12= 2.003205128
2.003205128 = $2.00

I hope this is right. XD
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The x-intercept will be the value of x when y=0.  The solutions to (x+1)(x+2)=0 are -1 and -2 since we can substitute them in to have one of the values in parentheses equal to zero, so our x-intercepts are (-1, 0) and (-2, 0).  The y-intercept is the value of y when x=0, or (0+1)(0+2)=2.  Therefore, the y-intercept is (0, 2).
3 0
3 years ago
Helpppp plssssss I need to get my grade up in math
KatRina [158]

Answer: 1.25 square feet

This converts to the improper fraction 5/4

===========================================================

Explanation:

The area of the triangle on the left is base*height/2 = 0.5*2/2 = 0.5 square feet. Note that 1/2 = 0.5

The area of the triangle on the right side is base*height/2 = 0.2*3/2 = 0.75 square feet. This converts to the fraction 3/4

Add up the two results: 0.5+0.75 = 1.25 square feet

-----------

If you need the answer as an improper fraction, then,

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3 0
3 years ago
Consider the following scenario:
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3 years ago
Thomas has $6.35 in dimes and quarters. The number of dimes is three more than three times the number of quarters. How many quar
mr Goodwill [35]

Answer:

He has 11 quarters

Step-by-step explanation:

* Lets study the information in the problem to solve it

- The value of dimes and quarters is $6.35

- There are dimes and quarters

- The dime = 10 cents

- The quarter = 25 cents

* We must change the money from dollars to cents

∵ $1 = 100 cents

∴ $6.35 = 6.35 × 100 = 635 cents

- The number of dimes = 3 + 3 × number of quarters

* Let number of dimes is D and number of quarter is Q

∴ D = 3 + 3Q

∴ 10D + 25Q = 635

* Substitute the value of D from first equation in the second equation

∴ 10(3 + 3Q) + 25Q = 635 ⇒ open the bracket

∴ 10(3) + 10(3Q) + 25Q = 635

∴ 30 + 30Q + 25Q = 635 ⇒ collect like terms

∴ 30 + 55Q = 635 ⇒ subtract 30 from both sides

∴ 55Q = 605 ⇒ divide both sides by 55

∴ Q = 11

* He has 11 quarters

5 0
3 years ago
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