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Reika [66]
4 years ago
10

Which of the following is a proportion? 3/4=12/15 8/10=6/8 6/9=8/12 4/6=9/12

Mathematics
2 answers:
ad-work [718]4 years ago
6 0
The answer is 6/9 =8/12 i think bro
Vinil7 [7]4 years ago
6 0
<h2>You didn't have to delete it. I tried answering your question in the box, but it didn't work. Our world is already broken because of people with egos like yours. Everyday you are given breathe, and at least you should choose to use that breathe wisely because any second this whole world can be taken away from you. So, all I ask is please be kind.</h2>
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Determine the diameter of the circle with the equation x 2+ y 2= 9.
kotegsom [21]

Answer: d = 6

Step-by-step explanation:

x^2 + y^2 = r^2

So r = 3 and d will be 2 x r = 6

6 0
3 years ago
Hi<br>What’s up y’all idek why I’m here
Usimov [2.4K]

Answer:

lol

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which event has exactly 12 possible outcomes?
lara [203]

Answer:

rolling a number cube with sides labeled 1 through 6 and tossing a coin.

Step-by-step explanation:

We will resolve each statement to determine the events that has exactly 12 possible outcomes.

N = number of possible outcomes for a cube

Nc = number of possible outcomes for a coin

Nca = number of possible outcomes for the cards

i. rolling a number cube with sides labeled 1 through 6 and then rolling the number cube again

Nt = N × N

N = 6 ( cube has 6 possible outcomes and its rolled twice)

Nt = 6 × 6 = 36

ii. tossing a coin and randomly choosing one of 4 different cards.

Nt = Nc × Nca

Nc = 2 ( coin has two outcomes)

Nca = 4 ( 4 possible cards )

B = 2 × 4 = 8

iii. rolling a number cube with sides labeled 1 through 6 and tossing a coin.

N = N × Nc

N = 6 ( cube has 6 possible outcomes)

Nc = 2 (coin has two faces)

N = 6 × 2 = 12 (correct)

Iv. tossing a coin 6 times.

N = Nc^6

Nc = 2

N = 2^6 = 64

Therefore, the correct answer is iii.

rolling a number cube with sides labeled 1 through 6 and tossing a coin.

3 0
3 years ago
Tutorial Exercise A boat leaves a dock at 2:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due
ANTONII [103]

Answer:

Both the boats will closet together at 2:21:36 pm.

Step-by-step explanation:

Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).

Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),

        Formula :   d=v*t

at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)

the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)

      Formula : D=\sqrt{(x2-x1)^2+(y2-y1)^2}

⇒                     D = \sqrt{20^2t^2+15(t-1)^2}

Now let           F(t) = D^2(t)

                ∵    F'(t) = 800t + 450(t-1) =  1250t -450\\F'(t) =0

⇒                     t= 450/1250

⇒                     t= .36 hours

⇒                       = 21 min 36 sec

Since F"(t)=0,

∴ This time gives us a minimum.

Thus, The two boats will closet together at 2:21:36 pm.

3 0
3 years ago
Choose the correct choice?!? I think it's A but not sure??
SpyIntel [72]
Your answer is right
3x^2 + 13x + 4
5 0
4 years ago
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