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3 years ago

CAN ANYONE PLEASE HELP ME ON THIS!!

Mathematics

1 answer:

GarryVolchara [31]3 years ago

7 0

Answer:

8. b

9.C

10.a

11.a

12. c

13. b

brainliest pls <3

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The number 0.0000000726 is equivalent to which of the following expressions?

Dimas [21]

Answer:

Step-by-step explanation:

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3 years ago

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2x2 − 1 = 3x + 4 Which equation correctly applies the quadratic formula?

NNADVOKAT [17]

Standard form: ax^2 + bx + c = y

Steps to simplify:

2x^2 - 1 = 3x + 4

~Subtract (3x + 4) to both sides

2x^2 - 1 - 3x + 4 = 3x + 4 - 3x + 4

~Simplify

2x^2 - 3x - 5 = 0

(a = 2, b = -3, c = -5)

Now that we know what these values are, we can use the quadratic formula to solve.

$x=\frac{-b-+\sqrt{b^2-4ac} }{2a} \\x = \frac{-(-3)-+\sqrt{-3^2-4(2)(-5)} }{2(2)}\\x= \frac{-3-+\sqrt{49} }{4} \\x=\frac{3-+7}{4} \\x = \frac{10}{4}~or~\frac{-4}{4} \\x=\frac{5}{2}~or~-1$

Answer: x = 5/2 or x = -1

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3 years ago

Pete corporation produces bags of peanuts. It's fixed cost is $18,900. Each bag sells for $2.17 with a unit cost of $1.27. What

pentagon [3]

Answer:

in units: 18,900

in dollars: $ 41,013

Step-by-step explanation:

The break even point is the sales dollar amount or sales in unit at whichthe operating income of the firm equals to zero: $\frac{Fixed\:Cost}{Contribution \:Margin} = Break\: Even\: Point_{units }$

Where:

$\frac{Contribution \: Margin}{Sales \: Revenue} = Contribution \: Margin \: Ratio$

<em><u>Contribution margin:</u></em>

2.17 - 1.27 = 1 dollar per unit

Break even:

$18,900 fixed cost / $1 per unit = 18,900 units

Then, in sales:

18,900 x $2.17 each = 41.013‬

break even point:

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3 years ago

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A snowboarder descends a 1200-foot hill in 3 minutes. What is the mean change in elevation per minute? (400 is not correct!)

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3 years ago

1. Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 c

prisoha [69]

Answer:

See explanation

Step-by-step explanation:

Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 chose the aisle seat, then

$P(\text{Window seat})=\dfrac{492}{806}=\dfrac{246}{403}\\ \\P(\text{Middle seat})=\dfrac{8}{806}=\dfrac{4}{403}\\ \\P(\text{Aisle seat})=\dfrac{306}{806}=\dfrac{153}{403}$

a) One randomly selected person preferes aisle seat with probability

$\dfrac{153}{403}$

b) Two randomly selected people both prefer aisle seat (with replacement) is

$\dfrac{306}{806}\cdot \dfrac{306}{806}=\dfrac{153}{403}\cdot \dfrac{153}{403}=\dfrac{23,409}{162,409}$

c) Two randomly selected people both prefer aisle seat (without replacement) is

$\dfrac{306}{806}\cdot \dfrac{305}{805}=\dfrac{153}{403}\cdot \dfrac{61}{161}=\dfrac{9,333}{64,883}$

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3 years ago