Let a =70° and b= 10° (and a-b=70-10 =60)
We have the following trigonometric identity:
sin(a-b) = sin(a).cos(b)-sin(b).cos(a) OR:
sin(70-10) = sin70.cos10 - sin10.cos70
But sin(70-10) = sin(60) and we know that sin(60°) =(√3)/2
Answer:
x = -6
Step-by-step explanation:
Distribute the 2 into the brackets:
2x + 10 = -2
leave the 2x alone on one side:
2x = -2 -10
2x = -12
divide both sides by 2:
x = -6
Answer:
3:2
Step-by-step explanation:
45, 30
both divisible by 15, so:
3 : 2
bc :
3*15 = 45
2*15 = 30
Answer: 2a+c
Step-by-step explanation: You add all variables that are positive then you subtract by negatives or vice versa. Add 3a+6a-7a yes subtract the 7a which gets you 2a. Add 8b+b-9b, you get 9b-9b which is 0 so you don’t need b in the problem anymore. -5a+4c+2c then you get c, because it is 1 c. So your answer is 2a+c. :P Hope this helped.
Answer:
Mariya's interval is wrong because it is not centered on the point estimate
Step-by-step explanation:
