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zubka84 [21]
3 years ago
7

Find m < RQP 70 55 80 90

Mathematics
1 answer:
Vinil7 [7]3 years ago
6 0
I believe the answer is 70 cause all you have to do is divide 140 by 2
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What is the answer to. Write a polynomial equation with integer coefficients that has the given roots, x=7 and x=-5
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3 years ago
Whats 407 divided by 47..<br>​
vovangra [49]

Answer:

8.65957446809

Step-by-step explanation:

8\frac{31 }{47}   8.7

6 0
3 years ago
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Please help!<br><br> If sin(xº)=cos(yº) find k if x=2k+3 and y=6k+7
USPshnik [31]

answer

10

step-by-step explanation

the equation given is sin(x) = cos(y) with x = 2k + 3 and y = 6k + 7

substitute in 2k+ 3 for x in sin(x) and substitute in 6k + 7 for y in cos(y)

sin(x) = cos(y)

sin(2k + 3) = cos(6k + 7)

we know that sin(x) = cos(90 -x)

sin(2k + 3)

= cos(90 - (2k + 3) )

= cos(90 - 2k - 3)

= cos(87 - 2k)

substitute this into the equation sin(2k + 3) = cos(6k + 7)

sin(2k + 3) = cos(6k + 7)

cos(87 - 2k) = cos(6k + 7)

87 - 2k = 6k +7

80 = 8k

k = 10

7 0
3 years ago
lucy took three tests. if her median score was 82 her mean score 87 and her range was 17 what were three scores
Tatiana [17]
Her scores would be 98, 82, and 81. Their sum would be 261 then you would divide it be 3 and it would give you 87 then to find the median line the numbers up from greatest to least and 82 would be in the middle. To find the range subtract 81 from 98 and it gives you 17. Did this help?
3 0
3 years ago
A deck of cards contains RED cards numbered 1,2,3,4,5, BLUE cards numbered 1,2,3, and GREEN cards numbered 1,2,3,4,5,6. If a sin
Tatiana [17]

Answer: 1/52

Step-by-step explanation:

A deck of cards contains 52 cards

Red cards are numbered 1,2,3

Blue cards are numbered 1,2,3,4,5,6

Green cards are numbered 1,2

Number of Red card = 3

Number of blue card = 6

Number of Green card = 2

Let Pr(R) = Probability of picking a Red card

Let Pr(B) = probability of picking a blue card

Let Pr(G) = probability of picking a green card

Let Pr(RE) = Probability of picking a red even card

Let Pr(RO) = probability of picking a red odd card

Let Pr(BE) =probability of picking a blue even card

Let Pr(BO) = probability of picking a blue odd card

Let Pr(GE) = probability of picking a green even card

Let Pr(GO) = probability of picking a green odd card

Pr(R) = 3/52

Since we have 3 red cards,

Pr(RE) = 1/3

Pr(RO) =2/3

Pr(B) = 6/52

= 3/26

Since we have 6 blue cards ,

Pr(BE) = 3/6

= 1/2

Pr(BO) = 3/6

= 1/2

Pr (G) = 2/52

= 1/26

Since we have 2 green cards,

Pr(GE) = 1/2

Pr(GO) = 1/2

The probability of picking a Green card and an odd green card is

Pr(G) n pr(GO)

1/26 * 1/2

= 1/52

5 0
3 years ago
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