2 years ago

How do you solve this (3y+1)^1/2=y-1

1 answer:

Vlad [161]2 years ago

5 0

Answer: y=-3

Step-by-step explanation:

(number)^1 is just (number)

so (3y+1)^1/2=y-1 is (3y+1)/2=y-1

multiply 2 on both side so get rid of fraction

then 3y+1=2(y-1)

3y+1=2y-2

y=-3

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