Answer:

Step-by-step explanation:
Give that:
the surface equation is 
from the family of traces in x = n given that
, the equation can be represented as :


This represents a family of hyperbola for all values of n expects that n = ± 1
So, if n = ± 1,
Then

(y-z) (y+z) = 0
y = ± z
So, for n = ± 1, it is a pair of line for y = z, y = -z
Answer:

Step-by-step explanation:

Here we can solve this in 2 ways ,
Method 1 :

Here the bases are equal. So,

Method 2 :

Here the exponents are same. So,
