1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shalnov [3]
3 years ago
10

Reread paragraph 4 which of these is evidence that helps to support the authors point

Mathematics
2 answers:
kirill [66]3 years ago
8 0

Answer:

what do paragraph 4 say?? send a picture

8090 [49]3 years ago
6 0
What does paragraph 4 says ? Please provide a image
You might be interested in
In the commutative property, order does not matter. However, this is not true when it comes to__ & __problems where order do
Luda [366]

Answer:

In the commutative property, order does not matter. However, this is not true when it comes to substraction & division problems where order does matter.

Step-by-step explanation:

Commutative property states that there is no change in result when the numbers in an expression are reversed. Commutative property is true for addition and multiplication but not for subtraction and division.

7 0
3 years ago
Read 2 more answers
If m ABC=25 and m CBD= 35 then m ABD=
RideAnS [48]

Answer:

Angle ABD = 60

Step-by-step explanation:

Angle ABD = angle ABC + angle CBD

We are given that angle ABC = 25 and angle CBD = 35

So angle ABD = 25 + 35 = 60

5 0
3 years ago
Read 2 more answers
Does anyone has Algebra ll and if so can you please help me with this problem 5i/-2-6i And also I can't pay you but I hope God c
asambeis [7]

Answer:

s = \frac{5i}{-2-6i} = -\frac{30}{40}-\frac{10}{40}i

Step-by-step explanation:

We have the following complex number s = \frac{5i}{-2-6i}, we proceed to simplify the expression as follows:

1) \frac{5i}{-2-6i} Given.

2) (5i)\cdot (-2-6i)^{-1} Definition of division.

3) [(5i)\cdot (-2-6i)^{-1}]\cdot [(-2+6i)\cdot (-2+6i)^{-1}] Modulative and associative properties/Existence of the additive inverser

4) [(5i)\cdot (-2+6i)]\cdot [(-2-6i)^{-1}\cdot (-2+6i)^{-1}] Commutative and associative properties.

5) [(5i)\cdot (-2+6i)]\cdot [(-2-6i)\cdot (-2+6i)]^{-1} a^{c}\cdot b^{c} = (a\cdot b)^{c}

6) [(5i)\cdot (-2+6i)]\cdot [4+36]^{-1}    (a+b)\cdot (a-b) = a^{2}-b^{2}/Definition of complex number/  a\cdot (-b) = -a\cdot b

7) [(5i)\cdot (-2)+(5i)\cdot (6i)]\cdot 40^{-1} Definition of sum.

8) (-10\cdot i+30\cdot i^{2})\cdot 40^{-1}    a\cdot (-b) = -a\cdot b/Associative and commutative properties.

9) (-30-10i)\cdot 40^{-1} Commutative properties/Definition of complex number/ a\cdot (-b) = -a\cdot b

10) -30\cdot 40^{-1}-(10i)\cdot 40^{-1} Distributive property.

11) -\frac{30}{40}-\frac{10}{40}i Definition of division/Result.

s = \frac{5i}{-2-6i} = -\frac{30}{40}-\frac{10}{40}i

6 0
3 years ago
Fine the volume of the figure below
vova2212 [387]
427.26inches is the answer
5 0
3 years ago
Read 2 more answers
HELP PLEASE I WILL GIVE BRAINLIEST
Ede4ka [16]
False
True
True

Needs 20 characters
3 0
3 years ago
Other questions:
  • What is the answer to: if T(n)=4n-1
    11·1 answer
  • All vertical and horizontal cross-sections of any one cube are all the same size and shape. What about vertical and horizontal c
    6·1 answer
  • If a = (a1, a2) and b = ax, then what is the dimension of span(a1, a2, b)? explain.
    14·1 answer
  • Kevin delivers newspapers in his town every morning. The amount he earns from delivering newspapers is given by y = 30x + 18, wh
    6·1 answer
  • A quadrilateral has one pair of parallel sides with lengths 1 3/4 inches and 1 1/4 inches, and two angles that measure 36 degree
    11·1 answer
  • How do you simplify 3x +10-8+2x​
    12·1 answer
  • Find the equation of a line that has slope, m, of 4 and passes through the point (10, 15).​
    7·1 answer
  • What is (2x+5y) (2x+5y)?​
    10·1 answer
  • I really need help on this question​
    8·1 answer
  • What is the value of x in the triangle?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!