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2 years ago

What Is the Title of This Picture?

Mathematics

1 answer:

dem82 [27]2 years ago

3 0

Please post the picture.

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Jason and Jill or two students in mr. White's math class. On the last 5 quizzes Jason scored an 80 90 95 85 and 70. Jill scored

Mrac [35]

Jason's scores : 80 90 95 85 70 and

Jill's score : 70 75 90 100 95.

Mean of Jason's scores = $\frac{80 + 90 + 95 + 85 + 70}{5}=\frac{420}{5}=84.$

Mean of Jill's scores = $\frac{70+75+90+100+95}{5}=\frac{430}{5}=86$

Now, in order to find the mean absolute deviation, need to find the difference of each score from means.

<u>Mean absolute deviation for Jason's scores.</u>

|84-80| = 4

|84-90| = 6

|84-95| = 9

|84-85| = 1

|84-70|= 14

$\frac{4+6+9+1+14}{5}=\frac{34}{5}=6.8$

<u>Mean absolute deviation for Jill's scores</u>

|86-70| = 16

|86-75| = 11

|86-90| = 4

|86-100| = 14

|86-95|= 9

$\frac{16+11+4+14+9}{5}=\frac{54}{5}=10.8$

Jill got average quiz score 86 and Jason got 84.

Therefore, Jill got better quiz average.

Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.

Therefore, Jason got more consistent grades.

8 0

3 years ago

What number is 0.68 more than 0.44?

natka813 [3]

Answer:

1.12

Step-by-step explanation:

0.68 + 0.44 = 1.12

3 0

3 years ago

Perform the indicated matrix row operation and write the new matrix

Ne4ueva [31]

The given operation involves just swapping the two rows, so carrying out $R_1\leftrightarrow R_2$ on the matrix gives

$\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]$

5 0

3 years ago

Are computers better than a straight edge and compass

serious [3.7K]

Answer:

Yes

Step-by-step explanation:

They are exact and you can't mess up or accidentally slide the compass or straightedge around. This is just my opinion though.

5 0

3 years ago

Read 2 more answers

How do I find the area

inn [45]

Wasssaa,

Steps:

To find the area of a triangle you multiply the base times the height, in this case the is (19m)
and the height is (11m), after you multipy those numbers you divide by (2)
$(19m \times 11m) \div 2$
$\frac{209 }{2}$

Answer:
$104.5sq \: m$
Hope this helped you
:D

8 0

3 years ago