Answer:
3.48cm³ (approximated)
Step-by-step explanation:
The maximum water that bowl can hold = The volume of the bowl

Radius is half of diameter.
<u>Given</u> -
<em>From</em><em> </em><em>the</em><em> </em><em>given</em><em> </em><em>data</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>derive </em><em>that</em><em> </em><em>the</em><em> </em><em>radius</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>hemispheri</em><em>cal</em><em> </em><em>bowl</em><em> </em><em>is</em><em> </em><em>5</em><em>c</em><em>m</em><em> </em><em>(</em><em>1</em><em>0</em><em>/</em><em>2</em><em>)</em>
Putting the known values into the formula to get the value of the volume of bowl :

= 3.48888cm³
= 3.48cm³
It’s 7 because it is on the exterior, and the other side, of the the parallel lines from 2.
-5a^2 - 7a = -a x (5a + 7)
let me know if you have any other questions
:)
Answer:
73.5
Step-by-step explanation:
circumference = 2πr , where r = radius
given radius = 11.7 so r = 11.7
C = 2πr
==> plug in r = 11.7
C = 2π(11.7)
==> multiply 2 and 11.7
C = 23.4π
==> multipl 23.4 and π
C = 73.5 ( rounded to the nearest tenth )
Answer:
x = 26.45
Step-by-step explanation:
Cos theta = adjacent side / hypotenuse
cos 50 = 17 /x
Switch the x and the cos 50
x = 17 / cos 50
x =26.44730506
Rounding to 2 decimal places
x = 26.45