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2 years ago

If RT= 19 meters, find LW.

Mathematics

1 answer:

Naddika [18.5K]2 years ago

6 0

Answer:

if RT = 19 meters, Find LE

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Two towns that are 31.5 km apart are 3 cm apart on a map. what is the scale of the map?

VLD [36.1K]

<u>Answer:</u>

1 cm : 10.5 km

<u>Step-by-step explanation:</u>

We are given that two towns are 31.5 km in real and are 3 cm apart on a map and we are to find the scale of the map.

For this, we can use the ratio method.

$\frac { 3 cm } { 1 c m } = \frac { 3 1 . 5 k m } { x }$

$x = \frac { 3 1 . 5 \times 1 } { 3 }$

$x = 1 0 . 5$

Therefore, the scale of the map would be 1 cm : 10.5 km.

8 0

3 years ago

Read 2 more answers

For what value of x does (x + 3)^2-5=0

ArbitrLikvidat [17]

Answer:

x = -3±sqrt( 5)

Step-by-step explanation:

(x + 3)^2-5=0

Add 5 to each side

(x + 3)^2-5+5=0+5

(x + 3)^2 = 5

Take the square root of each side

sqrt((x + 3)^2 )=±sqrt( 5)

x+3 = ±sqrt( 5)

Subtract 3 from each side

x+3-3 = -3±sqrt( 5)

x = -3±sqrt( 5)

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3 years ago

Which number line shows the solution set for |y-9| <12

RUDIKE [14]

Answer:

Option c

$y\geq-3$ or $y \leq 21$

Step-by-step explanation:

The absolute value is a function that transforms any value x into a positive number.

Therefore, for the function $f(x) = |x|$ x> 0 for all real numbers.

Then the inequation:

$|y-9| \leq 12$ has two cases

$(y-9)$ if $y \geq 9$ (i)

$-(y-9)$ if $y < 9$ (ii)

We solve the case (i)

$y \leq 9 + 12\\y\leq21$

We solve the case (ii)

$-y +9 \leq 12\\-y \leq 12-9\\y \geq -3$

Then the solution is:

$y\geq-3$ or $y \leq 21$

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2 years ago

Line QR goes through points Q(0,1) and R(2,7). which equation represents line QR

vodka [1.7K]

M= (7-1)/(2-0)=3
y=3x + c
plug in Q
1= 3 x 0 +c
=> c =-2
=> the equation represents line QR is y=3x -2

3 0

3 years ago

Read 2 more answers

Are these rates equivalent, 96 words typed for 3 minutes; 160 words typed for 5 minutes

monitta

<h2>Greetings</h2>

Answer:

Yes, they are.

Step-by-step explanation:

Lets simplify both rates to the rate typer per minute.

(m is minutes)

3m = 96

Divide both sides by 3:

$\frac{3m}{3} = \frac{96}{3}$

m = 32

So the rate is 32 words per minute.

5m = 160

Divide both sides by 5:

$\frac{5m}{5} = \frac{160}{5}$

m = 32

<h3>So because the rates per minute are the same, they are equivalent.</h3>
<h2>Hope this helps!</h2>

3 0

2 years ago