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Vikentia [17]
3 years ago
10

How to simplify 6 and 1/8

Mathematics
1 answer:
lozanna [386]3 years ago
6 0

Answer:

3 and 1/2

Step-by-step explanation:

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(2,5) and (3/2 ,2) find the slope of the line passing through the points.
larisa [96]

Answer:

6

Step-by-step explanation:

To find the slope 'm' we use 2 points from the line, those are given in the statement:

x_{1} =2\\y_{1} =5\\\\x_{2} =3/2\\y_{2} =2

m=\frac{y_{2} -y_{1} }{x_{2}-x_{1}}

m=\frac{2 -5 }{3/2-2}}

Finally  m=6

4 0
4 years ago
Find the geometric mean between 4 and 1/4. Show your work.
Darya [45]

Answer:

2.125

Step-by-step explanation:

3 0
3 years ago
which best describes your ability to calculate and describe relationships among area,perimeter and circumference
klemol [59]
Calculate circumference. You can do the math mentally with area & perimeter,but circumference is much more complex
7 0
3 years ago
Read 2 more answers
Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame
lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{207.9 - 208}{0.1678}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0
3 years ago
4 to the fourth negative power multiplied by four to the fifth power
Alex Ar [27]
Simplify the following:4^5/4^4
Combine powers. 4^5/4^4 = 4^(5 - 4):4^(5 - 4)
5 - 4 = 1:Answer: 4
3 0
3 years ago
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