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3 years ago

Six chicken nuggets have 204 calories. How many calories are in 9 chicken nuggets

Mathematics

2 answers:

professor190 [17]3 years ago

7 0

Answer:

306 calories

Step-by-step explanation:

By looking at the problem, we can conclude the number of chicken nuggets and the calories are directly related, when the amount of chicken nuggets go up, the calories also go up, proportionally. Because of this, we can set up an equation:

6 / 204 = 9 / x

Where x is the amount of calories in 9 chicken nuggets.

Now, we can simplify by cross multiplying:

6x = 1836

x = 306 calories

4vir4ik [10]3 years ago

3 0

Answer:

306 CS

Step-by-step explanation:

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You might be interested in

6=x/4-8 for x what equation do you get after adding 8 to each side

Lena [83]

Answer:

After adding 8 you get 14 = x/4.

Step-by-step explanation:

6=x/4-8 Add 8 to both sides:

6 + 8 = x/4 - 8 + 8

14 = x/4

x = 4*14

x = 56.

6 0

3 years ago

In a college student poll, it is of interest to estimate the proportion p of students in favor of changing from a quarter-system

Contact [7]

Answer:

n=206

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.09$ , we can use as prior estimate of p 0.5, since we don't have any other info provided, and we are interested in order to find the value of n, if we solve n from equation (a) we got: