PLEASE PLEASE PLEASE HELP ME SOMEBODY PLEASE!! LAST QUESTION!! PLEASE??
2 answers:
The proportion of students who like both building snowmen and skiing
<span>50/110 </span>
percent is 50/110 * 100 = 45%
<span>part b) </span>
Of the students who don't like building snowmen,
what is the probability of choosing a student who does not like skiing as well?
<span>There are 50 students who don't like building snowmen. </span>
There are 20 students who don't like skiing and don't like building snowmen.
<span>probability is is 20/50 = 2/5</span>
<span>50/110 </span>
percent is 50/110 * 100 = 45%
<span>part b) </span>
Of the students who don't like building snowmen,
what is the probability of choosing a student who does not like skiing as well?
<span>There are 50 students who don't like building snowmen. </span>
There are 20 students who don't like skiing and don't like building snowmen.
<span>probability is is 20/50 = 2/5</span>
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Answer:
Step-by-step explanation:
We know that:
In a deck of 52 cards there are 4 aces.
Therefore the probability of obtaining an ace is:
P (x) = 4/52
The probability of not getting an ace is:
P ('x) = 1-4 / 52
P ('x) = 48/52
In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.
For a discrete random variable V, the expected value is defined as:
Where V is the value that the random variable can take and P (V) is the probability that it takes that value.
We have the following equation for the expected value:
In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52
Therefore, expected value for V, the number of points obtained in the game is:
So: