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Sliva [168]
2 years ago
8

Please I need help please and thank u

Mathematics
2 answers:
kogti [31]2 years ago
5 0

Answer:

8x7

Step-by-step explanation:

s344n2d4d5 [400]2 years ago
4 0

Answer:

8x

Step-by-step explanation:

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BRAINLIEST!!!!!
Ksivusya [100]

Figure A best represents it because if you add 576 and 49 you get 625, which shows the theorem of a^2+b^2=c^2.

3 0
3 years ago
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Please help ! I am bad at math :(
nordsb [41]
The angles ∠ABC and ∠CBE together should equal 180º. 
∠ABC is 155º. 
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6 0
3 years ago
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What is the probability you roll doubles on two 6 sides dice <br> please show work
Mars2501 [29]

Answer:

1/6

Step-by-step explanation:

We can start by determining all the different combinations we can get.

We are using 6 sided dices, so we have a chance of getting 6 different numbers for each dice.

If we only have 1 dice, the our possible values would be:

1, 2, 3, 4, 5, 6

However, we have 2 dices. As such, our combinations have been multiplied, and now our possibilities are:

(1 , 1) , (1 , 2) , (1 , 3) , (1 , 4) , (1 , 5) , (1 , 6) , (2 , 1) , (2 , 2) , (2 , 3) , (2 , 4) , (2 , 5) , (2 ,6), and so on for 3, 4, 5, and 6

We can find the number of combinations by simply multiplying the amount of possible values for each dice.

Since both dices have 6 possible values, we multiply 6 by 6, and the amount of possible combinations is 36.

Now, let's determine the possibility for getting a double.

First, let's determine how many doubles we can get:

(1 , 1) , (2 , 2) , (3 , 3) , (4 , 4) , (5 , 5) , (6 ,6)

There are 6 different combinations for rolling a double.

So, our probability of rolling a double on two 6 sided dices is 6 out of 36

We can simplify that to 1 out of 6.

So the probability of rolling a double on two 6 sided dices is 1/6

8 0
2 years ago
La suma de un numero mas 16 es igual a 31
Simora [160]

Answer:

47

Step-by-step explanation:

8 0
2 years ago
Given LaTeX: f\left(x\right)=x^{^3}-3x+4f ( x ) = x 3 − 3 x + 4, determine the intervals where the function is increasing and wh
Vedmedyk [2.9K]

Answer:

Increasing: x and x>1.

Decreasing: -1

Step-by-step explanation:

We have been given a function f(x)=x^3-3x+4. We are asked to determine the intervals, where the function is increasing and where it is decreasing.

First of all, we will find critical points of our given function by equating derivative of our given function to 0.

Let us find derivative of our given function.

f'(x)=\frac{d}{dx}(x^3)-\frac{d}{dx}(3x)+\frac{d}{dx}(4)

f'(x)=3x^{3-1}-3+0

f'(x)=3x^{2}-3

Let us equate derivative with 0 as find critical points as:

0=3x^{2}-3

3x^{2}=3

Divide both sides by 3:

x^{2}=1

Now we will take square-root of both sides as:

\sqrt{x^{2}}=\pm\sqrt{1}

x=\pm 1

x=-1,1

We know that these critical points will divide number line into three intervals. One from negative infinity to -1, 2nd -1 to 1 and 3rd 1 to positive infinity.

Now we will check one number from each interval. If derivative of the point is greater than 0, then function is increasing, if derivative of the point is less than 0, then function is decreasing.

We will check -2 from our 1st interval.

f'(-2)=3(-2)^{2}-3=3(4)-3=12-3=9

Since 9 is greater than 0, therefore, function is increasing on interval (-\infty, -1) \text{ or } x.

Now we will check 0 for 2nd interval.

f'(0)=3(0)^{2}-3=0-3=-3

Since -3 is less than 0, therefore, function is decreasing on interval (-1,1) \text{ or } -1.

We will check 2 from our 3rd interval.

f'(2)=3(2)^{2}-3=3(4)-3=12-3=9

Since 9 is greater than 0, therefore, function is increasing on interval (1,\infty) \text{ or } x>1.

6 0
3 years ago
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