Answer:
1.4
Step-by-step explanation:
Answer:
The time taken for the projectile to reach the given height is 1.2 s.
Step-by-step explanation:
Given;
height of travel, h = 25 ft
initial velocity of the projectile, u = 15 ft/s
The time taken for the projectile to travel a height of 25 ft is given by the following kinematic equation;
h = ut + ¹/₂gt²
25 = 15t + ¹/₂(9.8)t²
25 = 15t + 4.9t²
4.9t² + 15t - 25 = 0
solving the quadratic equation, we will have the following solution of t;
t = 1.2 s
Therefore, the time taken for the projectile to reach the given height is 1.2 s.
Answer:
0.59375
Step-by-step explanation:
3f(x) - f(1/x) = x^2
x = 2: 3f(2) - f(1/2) = 2^2
x = 1/2: 3f(1/2) - f(2) = (1/2)^2
Let a = f(1/2) and b = f(2):
3b - a = 4; 3a - b = 1/4
3b - 4 = a
3(3b-4) - b = 1/4
8b = 12 + 1/4
b = 1.53125
3 * 1.53125 - 4 = a
a = 0.59375
Answer:
12
Step-by-step explanation:
4*3=12
i really hope this help u :)
1,126.25 hope this helped :)
