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Veronika [31]
3 years ago
6

1. 2x+5(6x-9)=1792. -40=6x-5(-4x-18)solve for X​

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0

Answer:

1. x = 7

2. x = -5

Step-by-step explanation:

1. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: 2*x+5*(6*x-9)-(179)=0

Pull out like factors  6x - 9  =   3 • (2x - 3)

 (2x +  15 • (2x - 3)) -  179  = 0

Pull out like factors: 32x - 224  =   32 • (x - 7)

Solve: x-7 = 0

Add  7  to both sides of the equation  = 7

2. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: -40-(6*x-5*(-4*x-18))=0

Pull out like factors: -4x - 18  =   -2 • (2x + 9)

 -40 -  (6x -  -10 • (2x + 9))  = 0

Pull out like factors:  -26x - 130  =   -26 • (x + 5)

-26 • (x + 5)  = 0

Solve: x+5 = 0

Subtract  5  from both sides of the equation: x = -5

Hope this helps! Please mark as brainliest.

Thanks!

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Using the distributive property method on 6x32 and 7x29
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2. A statistics student plans to use a TI-84 Plus calculator on her final exam. From past experience, she estimates that there i
Anarel [89]

Answer:

  1. P(≥1 working) = 0.9936
  2. She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.

Step-by-step explanation:

1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...

... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936

2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.

If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.

This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.

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My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)

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3 years ago
Tim installs 50 square feet on his floor in 45 minutes. At this rate, how long does it take him to install 495 square feet?
Katena32 [7]

Answer:

445.5 minutes

or 7 hours 25 minutes 30 seconds

Step-by-step explanation:

We can use ratio's to solve

50 ft^2           495 ft^2

--------------  = ------------

45 minutes    x minutes

Using cross products

50x = 45*495

50x=22275

Divide each side by 50

50x/50 = 22275/50

x =445.5

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If we want to convert to hours and minutes, divide by 60

7 hours is 420 minutes

445.5 -420 = 25.5

7 hours 25 minutes

.5 minutes is 30 seconds

7 hours 25 minutes 30 seconds

6 0
3 years ago
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