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Anton [14]
2 years ago
10

You have two exponential functions. One function has the formula g(x) = 3 x . The other function has the formula h(x) = 2-x . Wh

ich option below shows the graph of k(x) = (g - h)(x)?

Mathematics
1 answer:
Vlada [557]2 years ago
5 0

Answer:

see graph


Step-by-step explanation:

g(x) = 3^ x .

h(x) = 2^-x

We want to subtract them

f(x) = 3^x - 2^(-x)

I will rewrite without the negative exponent

f(x) = 3^x - (1/2)^(x)

Lets pick a couple of points

f(0)  = 3^0 - (1/2) ^ 0 = 1-1 = 0

As x gets large 3^x gets large and 1/2^x gets close to 0, so it will get large

As x goes to negative infinity, 3^x goes to zero and 1/2^ gets large  so we get - infinitity

You might be interested in
5(x + 3) - 2 = 2 + 5x + 9
Lunna [17]

Answer:

There is no solution

Step-by-step explanation:

5(x + 3) - 2 = 2 + 5x + 9

5x+15-2-2-5x-9=0\\15-13=0\\2=0

There is no solution

because 2=0 is not possible.

8 0
3 years ago
Read 2 more answers
2. Which of the following methods can't be used to find the zeros of a function?
ser-zykov [4K]

Answer:

The correct option is;

Substitute x = 0 in the function  and solve for f(x)

Step-by-step explanation:

The zeros of a function are the values of x which produces the value of 0 when substituted in the function

It is the point where the curve or line of the function crosses the x-axis

A. Substituting x = 0 will only give the point where the curve or line of the function crosses the y-axis,

Therefore, substituting x = 0 in the function  can't be used to find the zero's of a function

B. Plotting a graph of the table of values of the function will indicate the zeros of the function or the point where the function crosses the x-axis

C. The zero product property when applied to the factors of the function equated to zero can be used to find the zeros of a function

d, The quadratic formula can be used to find the zeros of a function when the function is written in the form a·x² + b·x + c = 0

5 0
3 years ago
Question:
Anuta_ua [19.1K]

Answer:

Step 1:

Addition is commutative

A + B = B + A

So the terms can be rearranged

Step 4:

2x(2x - 3) + 5(2x - 3)

Since (2x - 3) is common to both terms,

You can take it common

(2x - 3)(2x + 5)

This can be proved verified using distribution property

(2x - 3)(2x + 5) is the same as

(2x + 5)(2x - 3) because multiplication is commutative

3 0
3 years ago
A) Dos números enteros positivos se diferencian en 6 unidades y la suma de sus cuadrados
lianna [129]

Queremos encontrar dos números enteros tales que su diferencia sea de 6 y la suma de sus cuadrados sea igual a 260.

Veremos que los dos números son 8 y 14.

Primero, podemos definir esos números como A y B.

Entonces tenemos que:

A - B = 6

A^2 + B^2 = 260

Esto es un sistema de ecuaciones.

Para resolverlo, el primer paso es aislar una de las variables en una de las ecuaciones, vamos a hacer esto en la primera.

A - B = 6

A = 6 + B

Ahora reemplazamos esto en la otra ecuación.

A^2 + B^2 = 260

(6 + B)^2 + B^2 = 260

36 + 12*B + B^2 + B^2 = 260

36 + 12*B + 2*B^2 = 260

Ahora podemos resolver esto para B:

2*B^2 + 12*B + 36 - 260 = 0

2*B^2 + 12*B - 224

Las soluciones estan dadas por la formula de Bhaskara:

B = \frac{-12\pm \sqrt{12^2 - 4*2*(-224)} }{2*2} \\\\B =  \frac{-12 \pm 44 }{4}\\\\B =  (-3 \pm 11)

Entonces las dos soluciones son:

B = -3 + 11 = 8

B = -3 - 11 = -14

Sabemos que los números son positivos, asi que elejimos la primera, entonces tenemos:

B = 8.

Con esto podemos calcular el valor de A como:

A - B = 6

A = 6 + B = 6 + 8 = 14

Entonces los dos números son:

8 y 14.

Si deseas aprender más, puedes leer:

brainly.com/question/24761554

6 0
2 years ago
(4x^4y)^2<br> i need help
Bogdan [553]

Answer:

16x⁸y²

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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