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sergeinik [125]
3 years ago
9

Question 3 of 10

Mathematics
1 answer:
anyanavicka [17]3 years ago
7 0

no solution off the bus 60th and you can get

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NEED ANSWER ASAP WILL GIVE BRAINLIEST FOR CORRECT ANSWER
Arisa [49]

Answer:

y = 8x

Step-by-step explanation:

Since slope is 8/1 which is equal to 8 and x-intercept is 0.

Put these in slope-intercept equation i.e  y = mx + b

6 0
3 years ago
Read 2 more answers
The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for
lions [1.4K]

In the question it is given that,

The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for each flower

And the October price was a 20% increase of the September price.

Let the price of the flower in October be $x

So we have

x+  \frac{20}{100}x = 1.50 \\ \frac{120x}{100} = 1.50 \\ x = \frac{1.50*100}{120} = 1.25

So the price of the flower in Septembet is $1.25 .

7 0
3 years ago
Can someone help me with this ASAP plz
jeka57 [31]

Answer: The answer would be 0=0 I think.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the slope of the line passing through the pairs of points and describe the line as rising, falling, horizontal or vertical.
Anna [14]

Answer:

a.\ m=2,\ \text{the line is rising}\\\\b.\ m=-\dfrac{5}{4},\ \text{the line is falling}\\\\c.\ m=0,\ \text{the line is horizontal}\\\\d.\ m\ is\ unde fined,\ \text{the line is vertical}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

If

m > 0, then a line is rising

m < 0, then a line is falling

m = 0, then a line is horizontal

m is undefined, then a line is vertical

<h2>a.</h2>

(2, 1) and (4, 5)

m=\dfrac{5-1}{4-2}=\dfrac{4}{2}=2>0\to\text{rising}

<h2>b.</h2>

(-1, 0) and (3, -5)

m=\dfrac{-5-0}{3-(-1)}=\dfrac{-5}{4}=-\dfrac{5}{4}

<h2>c.</h2>

(2, 1) and (-3, 1)

m=\dfrac{1-1}{-3-2}=\dfrac{0}{-5}=0\to\text{horizontal}

<h2>d.</h2>

(-1, 2) and (-1, -5)

m=\dfrac{-5-2}{-1-(-1))}=\dfrac{-7}{0}\ \text{UNDEFINED}\to\text{vertical}

7 0
3 years ago
Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1
natali 33 [55]

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

r=\sqrt{(-5-(-2))^2+(3-1)^2}

r=\sqrt{(-5+2)^2+(2)^2}

r=\sqrt{(-3)^2+(2)^2}

On further simplification, we get

r=\sqrt{9+4}

r=\sqrt{13}

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and r=\sqrt{13}.

(x-(-2))^2+(y-1)^2=(\sqrt{13})^2

(x+2)^2+(y-1)^2=13

Therefore, the equation of the circle is (x+2)^2+(y-1)^2=13.

8 0
3 years ago
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