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Hitman42 [59]
2 years ago
10

A particular rocket is 15 ft tall. A model

Mathematics
1 answer:
m_a_m_a [10]2 years ago
6 0
It’s 5ft that’s litterly the easiest question I have ever seen
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Can someone help me? It's urgent and thank you!
BabaBlast [244]

Answer:

-1 and - 6

Step-by-step explanation:

Since you cannot have the denominator 0..... - 1 and - 6

make the denominator 0. Therefore they are excluded values

7 0
3 years ago
What is the volume of a cube with 1/2 inch sides pls answer I’ll give brainliest if you answer fast
Otrada [13]
1 Millimeter is the answer I hope this helps you.
3 0
3 years ago
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Please answer the following question:
ludmilkaskok [199]

Answer:

99 cm²

Step-by-step explanation:

1/2 BH

1/2 18 x 11

9 x 11

99

3 0
3 years ago
Simplify 8^-5 over 8^-3
Alex

Answer:

64-5 divided by 64-3 is 59 divided by 61. 59

8 squared is equal to 64.                           -----

                                                                     61

Step-by-step explanation:

7 0
3 years ago
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Please Please Please help with this math problem
katovenus [111]
  1. The revenue as a function of x is equal to -x²/20 + 920x.
  2. The profit as a function of x is equal to -x²/20 + 840x - 6000.
  3. The value of x which maximizes profit is 8,400 and the maximum profit is $3,522,000.
  4. The price to be charged to maximize profit is $500.

<h3>How to express the revenue as a function of x?</h3>

Based on the information provided, the cost function, C(x) is given by 80x + 6000 while the demand function, P(x) is given by -1/20(x) + 920.

Mathematically, the revenue can be calculated by using the following expression:

R(x) = x × P(x)

Revenue, R(x) = x(-1/20(x) + 920)

Revenue, R(x) = x(-x/20 + 920)

Revenue, R(x) = -x²/20 + 920x.

Expressing the profit as a function of x, we have:

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = -x²/20 + 920x - (80x + 6000)

P(x) = -x²/20 + 840x - 6000.

For the value of x which maximizes profit, we would differentiate the profit function with respect to x:

P(x) = -x²/20 + 840x - 6000

P'(x) = -x/10 + 840

x/10 = 840

x = 840 × 10

x = 8,400.

For the maximum profit, we have:

P(x) = -x²/20 + 840x - 6000

P(8400) = -(8400)²/20 + 840(8400) - 6000

P(8400) = -3,528,000 + 7,056,000 - 6000

P(8400) = $3,522,000.

Lastly, we would calculate the price to be charged in order to maximize profit is given by:

P(x) = -1/20(x) + 920

P(x) = -1/20(8400) + 920

P(x) = -420 + 920

P(x) = $500.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

3 0
2 years ago
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