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4 years ago

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Asquare and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of t

he circle. What is the ratio of the area of the square to the area of the circle? Express your answer as a common fraction in terms of $\pi$.

1 answer:

Musya8 [376]4 years ago

4 0

Answer:

1/π

Step-by-step explanation:

r = the side of the square and the radius of the circle

square area = r∧2/π·r∧2

r∧2 should cancel each other in the numerator and denominator.

The result is 1/π

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I need help ASAP will give brainliest

Tems11 [23]

Answer:

658 + 342 = 1000.

Step-by-step explanation:

Let x be the multiple of 47 and y be the multiple of 19 which gives 1000 while adding.Hence 47x + 19y = 1000On multiplying, find x and yX=14 and y=18So, 47*14= 658 and 19*18= 342 On adding, 658+342=1000Therefore, 658 and 342 are the two parts of 1000.

in simple way

47a + 19b = 1000

a = 14, b = 18

check: 14 x 47 = 658, 18 x 19 = 342, 658 + 342 = 1000.

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3 years ago

Read 2 more answers

For what value of k is there one solution to the given quadratic equation (k+1)x²+4kx+2=0.

andriy [413]

Answer:

If $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

The signal of $\bigtriangleup$ determines how many real roots an equation has:

$\bigtriangleup > 0$ : Two real and different solutions

$\bigtriangleup = 0$ : One real solution

$\bigtriangleup < 0$ : No real solutions

In this problem, we have the following second order polynomial:

$(k+1)x^{2} + 4kx + 2 = 0$ .

This means that $a = k+1; b = 4k; c = 2$

It has one solution if

$\bigtriangleup = 0$

$b^{2} - 4ac = 0$

$16k^{2} -8(k+1) = 0$

$16k^{2} - 8k - 8 = 0$

We can simplify by 8

$2k^{2} - k - 1 = 0$

The solution is:

$k = 1$ or $k = -\frac{1}{2}$

So, if $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

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3 years ago

What is 13.62 divided by -3.14?

Alex Ar [27]

Answer:

-4.3375796178343949044585987261146‬

Step-by-step explanation:

you can probably round it off but that is what my calculator gave me.

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$ax^2+bx+c=0$
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4 years ago