The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
Learn more on polynomial here: brainly.com/question/2833285
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Answer:
Did u get the answer yet i need it
Step-by-step explanation:
Answer:
4:9
Step-by-step explanation:
To take the scale factor from distance to area, we square it
2:3 distance
Square each term
2^2 : 3^2 area
4:9
Answer:
Step-by-step explanation:
subtract llol
first 1
x . y
1 . 2
3 . 4 rewrite =y/x
2-4/1-3
-2/2=-1
do for the rest bye
