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antiseptic1488 [7]
3 years ago
8

a cylindrical bucket has a radius of 6 inches and a height of 18 inches. What is the minimum number of buckets of water needed t

o completely fill a spherical storage tank that has a radius of 15 inches?
Mathematics
1 answer:
ivanzaharov [21]3 years ago
5 0

Answer:

Minimum 7 buckets of water is needed to completely fill spherical storage tank.

Step-by-step explanation:

We are given the following in the question:

Cylindrical bucket:

Radius, r = 6 inches

Height = 18 inches

Volume of bucket = Volume of cylinder

V = \pir^2 h \\V = 3.14\times (6)^2\times 18\\V =2034.72\text{ cubic inches}

Spherical storage tank:

Radius, r = 15 inches

Volume of tank = Volume of sphere =

V =\dfrac{4}{3}\pi r^3\\\\\V = \dfrac{4}{3}\times 3.14\times (15)^3\\\\V = 14130\text{ cubic inches}

Number of baskets required =

n = \dfrac{\text{Volume of tank}}{\text{Volume of bucket}}\\\\n =\dfrac{14130}{2034.72} = 6.94 \approx 7

Thus, minimum 7 buckets of water is needed to completely fill spherical storage tank.

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You can use the distance formula to solve this.

Distance Formula:
d = \sqrt{(X_2 -X_1)^2 + (Y_2 - Y_1)^2}

I am going to use point (3,2) as point 1 and (-1,-4) as point 2
Insert the points into the formula
d = \sqrt{(X_2 -X_1)^2 + (Y_2 - Y_1)^2}
d = \sqrt{((-1) - 3)^2 + ((-4) - 2)^2}
Solve:
d = \sqrt{((-1) - 3)^2 + ((-4) - 2)^2}
d = \sqrt{(-4)^2 + (-6)^2}
d = \sqrt{16 + 36}
d = \sqrt{52}
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d = \sqrt{52} = 2 \sqrt{13}
d = 2 \sqrt{13}
radius = 2 \sqrt{13} = 7.2111


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