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2 years ago

Please answer me fast plz

Mathematics

1 answer:

yulyashka [42]2 years ago

7 0

Answer:

find the classmark of each interval

forexample
(140+150)/2
(150+160)/2

do the same up to (190+200)/2

then

draw a graph by using frequently (number of weeks) on y-axis against classmark on x-axis

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Solve for x : <br><br><img src="https://tex.z-dn.net/?f=%5Cqquad%20%5Crightarrow%5Cbf%204x%20%2B%209x%20%2B%202x%20%3D%2030" id=

Lubov Fominskaja [6]

Answer:

x=2

Step-by-step explanation:

combine like terms to get 15x=30. divide by 15 on both sides to get x=2

4 0

1 year ago

Read 2 more answers

The circumference of a circle is 60 pi cm. What is the radius of the circle?

Artyom0805 [142]

Answer:

30/pi cm

Step-by-step explanation:

2×pi×r =60

r = 60/2×pi =30/pi

4 0

2 years ago

HELP!!!

ella [17]

Answer:

120

Step-by-step explanation:

We are given that the function for the number of students enrolled in a new course is $f(x) = 4^{x}-1$ .

It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.

We know that the average rate of change is given by,

$A = \frac{f(x)-f(a)}{x-a}$ ,

where f(x)-f(a) is the change in the function as the input value (x-a) changes.

Now, the number of students enrolled at 4 = f(4) = $f(x) = 4^{4}-1$ = 255 and the number of students enrolled at 2 = f(2) = $f(x) = 4^{2}-1$ = 15

So, the average increase $A=\frac{f(4)-f(2)}{4-2}$ = $A=\frac{255-15}{4-2}$ = $A=\frac{240}{2}$ = 120.

Hence, the average increase in the number of students enrolled is 120.

3 0

3 years ago

What is (6^3)^4 simplified

Sophie [7]

Step-by-step explanation:

$( {6}^{3})^{4} = {6}^{3 \times 4} = {6}^{12} \\$

7 0

2 years ago

What’s does 2+2 evaluation to

topjm [15]

Answer:4

Step-by-step explanation:

2+2 = 4

Adding 2 in 2 gives us 4.

4 0

2 years ago

Please answer me fast plz ​

Please answer me fast plz