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tatuchka [14]
3 years ago
11

Y=x+6x+y=8now graph 3 points on the line x+y=8​

Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0

Answer:

y=2

Step-by-step explanation:

advgdsfh usb hey do f ft h

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boyakko [2]
C, 80-75=5 and 95-90=5. Meaning your answer would be 5!
7 0
2 years ago
Read 2 more answers
Please help. Thank you
Inessa [10]

Given:

PQRS\sim TUVW

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

PQRS\sim TUVW

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

k=\dfrac{VW}{RS}

k=\dfrac{25}{35}

k=\dfrac{5}{7}

Therefore, the scale factor from PQRS to TUVW is k=\dfrac{5}{7}.

6 0
3 years ago
Kiera and Trina joined a gym. The gym offers two different payment plans. Kiera chose Plan 1 and pays $25 a month and no fee to
Lady_Fox [76]

Answer:

t1 = $25m

t2 = $(10m + 100)

Step-by-step explanation:

Here we want to write equations

Kiera chose plan 1

$25 monthly and no joining fee

So the amount after m months will be 25 * m

t1 = $25m

Trina chose plan 2

$10 a month and $100 joining fee

after m months , total payment will be

10(m) + 100 = $(10m + 100)

Thus t1 = $25m and t2 = $(10m + 100)

6 0
3 years ago
The difference of two numbers is 8. If the sum of the smaller number and the square of the larger
galben [10]

Answer:

12

Step-by-step explanation:

12^2 is the greatest number that is closest to 148. then there is 4 as the smaller number 12-4=8

144+4=148

6 0
3 years ago
Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.
alexgriva [62]
Recall that

|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

There are three cases to consider:

(1) When x+2, we have |x+2|=-(x+2) and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4

(2) When x+2\ge0 and x-2, we get |x+2|=x+2 and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)+(x+2)=4

(3) When x-2\ge0, we have |x+2|=x+2 and |x-2|=x-2, so

|x-2|+|x+2|=(x-2)+(x+2)=2x

So

|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x
4 0
3 years ago
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