Answer:
number of adults tickets sold = x = 90
number of teachers tickets = y = 45
number of students tickets = z = 145
Step-by-step explanation:
Cost of tickets
Adults = $6
Teachers = $4
Students = $2
Total tickets sold = 280
Total revenue = $1010
Let
x = number of adults tickets
y = number of teachers tickets
z = number of students tickets
x + y + z = 280
6x + 4y + 2z = 1010
If the number of adult tickets sold was twice the number of teacher tickets
x = 2y
Substitute x=2y into the equations
x + y + z = 280
6x + 4y + 2z = 1010
2y + y + z = 280
6(2y) + 4y + 2z = 1010
3y + z = 280
12y + 4y + 2z = 1010
3y + z = 280 (1)
16y + 2z = 1010 (2)
Multiply (1) by 2
6y + 2z = 560 (3)
16y + 2z = 1010
Subtract (3) from (2)
16y - 6y = 1010 - 560
10y = 450
Divide both sides by 10
y = 450/10
= 45
y = 45
Substitute y=45 into (1)
3y + z = 280
3(45) + z = 280
135 + z = 280
z = 280 - 135
= 145
z = 145
Substitute the values of y and z into
x + y + z = 280
x + 45 + 145 = 280
x + 190 = 280
x = 280 - 190
= 90
x = 90
Therefore,
number of adults tickets sold = x = 90
number of teachers tickets = y = 45
number of students tickets = z = 145
Answer:
2a^2+−11
Step-by-step explanation:
Combine Like Terms:
=2a^2+−5+ −6
=(2a^2)+(−5+ −6)
=2a^2+−11
Answer:
Income on man from sunday to thursday
=75+75+75+75+75= 375
Income on friday- 93
= 375+93= 468
468÷6= 78.
Answer:
125%
Step-by-step explanation:
this is because the difference is 25% so b is 125% more than a
2y+6x=0
-6x from both sides
2y=-6x+0
then divide by 2 to each side so it looks like this 2y/2=-6x+0/2
the 2 cancels 2y so you're left with y
Then divide -6/2=-3 and 0/2=0
y=-3x+0
Does that answer your question?