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3 years ago

A person purchased 5k + 2 items for a total cost of 35k 2 + 29k + 6. Find the average cost per item of this purchase.

Mathematics

1 answer:

olchik [2.2K]3 years ago

7 0

Answer:

$\boxed{7k + 3}$

Step-by-step explanation:

Average cost = total cost/number of items = (35k² + 29k + 6)/(5k + 2)

Perhaps the best way to solve this problem is to use long division.

7k + 3

5k + 2)35k² + 29k + 6

35k² + 14k

15k + 6

15k + 6

Thus,

$\frac{35k^{2}+29k+ 6}{5k + 2} = 7k+3$

The average cost per item is $\boxed{7k+3}$ .

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What is the answer to 5-10x<-145

Nuetrik [128]

Answer:

x > 15

Step-by-step explanation:

So here we have to find the value of x

So, Subtract 5 from both sides;

-10x < -5 - 145

Now collect like terms,

-10x < -150

Divide both sides by -10

x > 15

The sign changes because if an equality is divided by a negative number the sign automatically changes.

7 0

2 years ago

An urn contains 5 red balls and 2 green balls. Two balls are drawn one after the other. What is the probability that the second

AleksAgata [21]

Answer:

The probability that the second ball is red is 71%

Step-by-step explanation:

Probabilities

We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).

The first ball can be red (R) or green (G). The probability that it's red is computed by

$\displaystyle P(R)=\frac{5}{7}$

The probability is's green is computed by

$\displaystyle P(G)=\frac{2}{7}$

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

$\displaystyle P(RR)=\frac{5}{7}\cdot \frac{4}{6}=\frac{10}{21}$

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

$\displaystyle P(GR)=\frac{2}{7}\cdot \frac{5}{6}=\frac{5}{21}$

The total probability of the second ball being red is

$\displaystyle P(XR)=\frac{10}{21}+\frac{5}{21}=\frac{5}{7}=0.71$

The probability that the second ball is red is 71%

7 0

2 years ago

What is the area of a circle with a radius of 5

V125BC [204]

The answer to your question if the following : Pi x 25

5 0

2 years ago

Read 2 more answers

A fossil was analyzed and determined to have a carbon-14 level that is 80 % that of living organisms. the half-life of c-14 is 5

liq [111]

Answer:

The fossil is 1860 years old.

Step-by-step explanation:

The equation for the amount of fossil has the following format:

$Q(t) = Q(0)e^{rt}$

In which Q(t) is the amount after t years, Q(0) is the initial amount and r is the rate of change.

Half-life of c-14 is 5730 years.

This means that $Q(5730) = 0.5Q(0)$

$Q(t) = Q(0)e^{rt}$

$0.5Q(0) = Q(0)e^{5730r}$

$e^{5730r} = 0.5$

$\ln{e^{5730r}} = \ln{0.5}$

$5730r = \ln{0.5}$

$r = \frac{\ln{0.5}}{5730}$

$r = -0.00012$

$Q(t) = Q(0)e^{-0.00012t}$

How old is the fossil?

This is t for which

$Q(t) = 0.8Q(0)$

$Q(t) = Q(0)e^{-0.00012t}$

$0.8Q(0) = Q(0)e^{-0.00012t}$

$e^{-0.00012t} = 0.8$

$\ln{e^{-0.00012t}} = \ln{0.8}$

$-0.00012t = \ln{0.8}$

$t = -\frac{\ln{0.8}}{-0.00012}$

$t = 1860$

The fossil is 1860 years old.

4 0

2 years ago

Please help with my math i took a picture of it

Fynjy0 [20]

Answer:

40°

Step-by-step explanation:

Supplementary angles add up to 180°. Complementary angles add up to 90°.

m∠1 + m∠2 = 180°

115° + m∠2 = 180°

m∠2 = 65°

m∠2 + m∠3 = 90°

65° + m∠3 = 90°

m∠3 = 25°

m∠2 − m∠3 = 65° − 25° = 40°

6 0

2 years ago