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LUCKY_DIMON [66]
3 years ago
11

A triangle has vertices at A(–2, 4), B(–2, 8), and C(6, 4). If A prime has coordinates of (–0.25, 0.5) after the triangle has be

en dilated with a center of dilation about the origin, which statements are true? Check all that apply. The coordinates of C prime are (0.75, 0.5). The coordinates of C prime are (1.5, 1). The scale factor is One-eighth. The scale factor is 8. The scale factor is One-fourth. The scale factor is 4. The coordinates of B prime are (–0.25, 1). The coordinates of B prime are (–0.5, 2).
Mathematics
2 answers:
Eddi Din [679]3 years ago
4 0

Answer:

✅     The coordinates of C prime are (0.75, 0.5).

The coordinates of C prime are (1.5, 1).

✅      The scale factor is One-eighth.

The scale factor is 8.

The scale factor is One-fourth.

The scale factor is 4.

✅      The coordinates of B prime are (–0.25, 1).

The coordinates of B prime are (–0.5, 2).

Step-by-step explanation:

FOR short 1,3,7

kati45 [8]3 years ago
3 0

Answer:

A,C,G

Step-by-step explanation:

I hoped I helped

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Mr. Wonka optimized your team’s box to maximize chocolate bar sales. The new volume is (x^3-9x) inches ^3, the length is (x+3) a
lyudmila [28]

Answer:

x^2-3x

Step-by-step explanation:

If we use polynomial division

          x^2-3x

x+3 | x^3+0x^{2} -9x

         <u> </u>x^3+3x^2<u>               </u>

                -3x^2-9x

         <u>       </u>-3x^2-9x<u>      </u>

                            0

8 0
3 years ago
Smallest of 3 consecutive positive intergers if the product of the smaller two intergers is 5 less than 5 times the largest inte
amm1812

What a delightful little problem ! (Partly because I could see
right away how to do it, and had the answer in a few minutes,
after a lot of impressive-looking algebra on my scratch-paper.)

Three consecutive integers are . . . x,  x+1,  and  x+2

The smallest two are . . . x  and  x+1
    Their product is . . . . . x(x+1)

5 times the largest one is . . . 5(x+2)
      5 less than that is . . . . . . 5(x+2)-5

Now, the conditions of the problem say that    <u>x (x + 1) = 5 (x+2) - 5</u>
THAT's the equation we have to solve, to find 'x' .

       Eliminate parentheses:    x² + x = 5x + 10 - 5
            Combine like terms:    x² + x = 5x + 5
Subtract 5x from each side:    x² - 4x = 5
Subtract  5  from each side:   <u>x² - 4x - 5 = 0</u>

You could solve that by factoring it, or use the quadratic equation.

Factored, it says that    (x + 1) (x - 5) = 0

From which       <em>x = -1</em>
             and      <em>x = +5</em>

We only want the positive results, so our three consecutive integers are

             5,  6,  and  7 .   

To answer the question, the smallest one is    <em><u>5 </u></em>.

<u>Check</u>:

   5 x 6  ? = ?  (7 x 5) - 5

       30  ? = ?  (35) - 5

         30   =   30

             yay !   


6 0
3 years ago
If f (x) = 2 x + 5 and three-halves are inverse functions of each other and f (x) = 2x + 5, what is
marusya05 [52]

Answer:

See explanation

Step-by-step explanation:

The question has conflicting details

f(x) = 2x + 5

f(x) = 2x + 5 and three halves doesn't sound correct.

So, I will take f(x) as

f(x) = 2x + 5

Next, solve for the inverse function

Replace f(x) with y

y = 2x + 5

Swap x and y

x = 2y + 5

Make 2y the subject

2y = x-5

Make y the subject

y = \frac{x-5}{2}

Replace y with the inverse sign

f^{-1}(x) = \frac{x-5}{2}

So, now we can calculate any value from the original function and from the inverse function.

For instance:

f^{-1}(7) = \frac{7-5}{2} = \frac{2}{2} = 1

f(1) = 2*1 + 5 = 2+5=7

7 0
3 years ago
...... please help with this Page
soldi70 [24.7K]
<span>#1 is C
</span><span>#2 is B
</span>3a is On the circle
<span>3b is inside
</span><span>3d is on
</span><span>3e is outside
</span>
<span>4a is "You can find if a triangle is right by using the Pythagorean theorem or by using perpendicular lines"
</span><span>4b): Using the Pythagorean Side AC (which is √10 units long)^2 + side AB (which is √40 units long)^2 is equal to 50 (which is the length of side BC). Using perpendicular lines, you find that line AB has a slope of 1/3 and side AC has a slope of -3. Since these two are opposite reciprocals, they are perpendicular, which means that they form a 90 degree angle.
</span><span>5.) To find the midpoint, use the formula (x2+x1/2,y2+y1/2) by using the given coordinates, we find that the midpoint is (1,-2). This point lies in quadrant IV, so it is proven that it's midpoint lies in quadrant IV.
</span>
:)
3 0
4 years ago
Help me plssssssssssssssssssssssss
natka813 [3]

Answer:

C

Step-by-step explanation:

Minus two equations , we got:

9x-9y= 132-(-12)

9x-9y=144

x-y=16

5 0
3 years ago
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