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saw5 [17]
3 years ago
8

The ratio of Sally’s CDs to Ray’s CDs is 2: 7. Ray has 49 CDs. If Ray gives Sally 21 CDs, what will be the new ratio of Sally’s

CDs to Ray’s?
Mathematics
1 answer:
densk [106]3 years ago
3 0
Sally's CDs to Ray's CDs = 2:7
2 + 7 = 9
Ray's Cds to all CDs is 7:9

2x + 7x = 9x

2x + 49 = 9x

-7x = -49

x = 7

Ray has 7x = 49
Sally has 2x = 14

14:49 is the same as 2:7

Ray has 49 CDs. Sally had 14 CDs.
Ray gives 21 CDs to Sally.

Ray: 49 - 21 = 28
Sally: 14 + 21 = 35

Sally's CDs to Ray's CDs = 35:28 = 5:4
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3 years ago
Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the
Black_prince [1.1K]

Answer:

a)  P(2)=0.270

b) P(X>3)=0.605

c)  P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the  Poisson distribution:

\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}

a)  In this case: \lambda=2.1

P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270

Therefore, the probability is P(2)=0.270.

b)  In this case: \lambda=2\cdot 2.1=4.2

P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605

Therefore, the probability is P(X>3)=0.605.

c)  We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: \lambda=2\cdot 2.1=4.2

P(X\geq 5)=1-P(X

Therefore, the probability is P=0.410.

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3 years ago
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Contact [7]

Answer:

J. 20

Step-by-step explanation:

6 0
2 years ago
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