Jabari is power washing houses for a summer job. For every job, he charges an initial fee plus $30 for each hour of work. His total fee for a 4 -hour job, for instance, is $170 . Jabari's total fee,f, for a single job is a function of the number,t, of hours it takes him to complete the job. Write the function's formula.

<h3><u>Answer:</u></h3>

f = 50 + 30t is the function formula for total fee of Jabari

<h3><u>Solution:</u></h3>

Let the initial fee be "x"

Let "t" be the number of hours invested in that work

Let "f" be the total fee of Jabari

He charges and initial fee plus 30$ for each hour of work

Therefore, total fee is given as:

Total fee = initial fee + 30(number of hours)

$f= x + 30t$

Thus the function formula is found

<h3><u>Find the initial fee:</u></h3>

Given that,

His total fee for a 4 -hour job, for instance, is $170

Therefore,

t = 4

f = 170

Thus we get,

$170 = x + 30(4)\\\\170 = x + 120\\\\x = 170 - 120\\\\x = 50$

<em><u>Thus the formula becomes,</u></em>

$f = 50+30t$

Thus the total fee is a function of number of hours it takes him to complete the job

5 0

4 years ago

The sum of n and the product 3 times n = 12. What is n? (Show your equation and at

aleksley [76]

N = 3

Step-by-step explanation: If you do the equation it comes out to n=4

n+3n=12

4n=12

n=3

You have to add the like terms then divide it so the variable is by itself. And whatever you do to one side, you have to do to the other

5 0

3 years ago

What is the slope of the line?

11Alexandr11 [23.1K]

Answer:

1/2

Step-by-step explanation:

7 0

3 years ago

How does the graph of y= -(2x+6)^2+3 compare to the graph of a parent function

raketka [301]

Here the list of the transformations applied to the parent function, and their effect:

$x^2 \to (2x)^2=4x^2$ . This causes a horizontal compression of factor 4.
$(2x)^2 \to (2x+6)^2= 4(x+3)^2$ . This causes a horizontal translation, 3 units to the left.
$(2x+6)^2 \to -(2x+6)^2$ . This causes a reflection about the x axis.
$-(2x+6)^2 \to -(2x+6)^2+3$ . This causes a vertical translation, 3 units up

So, if you start from the graph of $y=x^2$ , you have to compress and translate it horizontally, flip it with respect to the x axis, and finally move it up 3 units.

7 0

4 years ago