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3 years ago

A river raft holds at most 8 people. The guide and 2 people are already on board. How many more people can board the raft?

2 answers:

7 0

if the raft holds at least 8 people and there is already 2 on there then 8-2=6 so 6 people will be able to get on board if i did it correctly

Step-by-step explanation:

Deffense [45]3 years ago

5 0

Answer:

The answer is 5 more people can board the raft.

Step-by-step explanation:

If the raft can hold 8 people and there are 2 passengers and 1 guide already on board, and since 2 + 1 = 3, and 8 - 3 = 5, then that means that there is enough room in the raft for 5 more people.

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Joe runs each lap in 5 minutes. He will run at least 12 laps today. What are the possible numbers of minutes he will run today?

worty [1.4K]

Answer:

at least 60 min (1 hour)

Step-by-step explanation:

we know that a lap takes 5 min.

and we know he will run At least 12 laps

that means that the least number of min.he can run is 5x12=60

So, 60min is the answer

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4 years ago

Which one is the least?<br> 1/8, 1.125, or 2/5?<br> Then after which one is bigger?

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Answer:

1/8 is smaller than 2/5, and 2/5 is smaller than 1.125

Step-by-step explanation:

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2 years ago

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3 years ago

A survey conducted by a leading HMO found that of 2000 women, 340 were heavy smokers and 25 had emphysema. Of those who had emph

belka [17]

Answer:

The events being a heavy smoker and having emphysema are not independent.

Step-by-step explanation:

We are given the following in the question:

Number of women = 2000

Number of heavy smoker = 340

Number of women who has emphysema = 25

Number of women who has emphysema and are heavy smoker = 21

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

P(Smoker) =

$P(S) = \dfrac{340}{2000}=0.17$

P(emphysema) =

$P(E) = \dfrac{25}{2000}= 0.0125$

P(Smoker and emphysema) =

$P(S\cap E) = \dfrac{21}{2000} = 0.0105$

Two events A and B are said to be independent if

$P(A\cap B)=P(A)\times P(B)$

Checking conditions for independence:

$P(S)\times P(E) = 0.17\times 0.0125=0.002125\\P(S)\times P(E) \neq 0.0105\\P(S)\times P(E)\neq P(S\cap E)$

Thus, the events being a heavy smoker and having emphysema are not independent.

3 0

3 years ago

A river raft holds at most 8 people. The guide and 2 people are already on board. How many more people can board the raft?​

A river raft holds at most 8 people. The guide and 2 people are already on board. How many more people can board the raft?