We can readily know the x^2-4x+4=3y then use it to replace the same function in the first equation which refers to the 3y+y^2-6y=0
y^2-3y=0
y(y-3)=0
y1=0 -----------y2=3
Let's use a for number of days when he shot 50 shots and b for number of days when he shot 100 shots.
We have:
a + b = 20
We also know that he shot total of 1250 shots:
50a + 100 b = 1250
We have two equations. We can solve them for a and b. Let's rearange first equation for a:
a= 20 - b
We insert this into second equation:
50 * (20 - b ) + 100b = 1250
1000 - 50b + 100b = 1250
50b = 250
b = 5
a = 20 - 5
a = 15
Mark shot 100 shots on 5 days.
You need to find two factors of 20 that are consecutive: 4,5.
Answer: 5inx4in
Answer:
Step-by-step explanation:
- cotx cos x - cot x = 0
- cotx( cosx - 1) = 0
1. <u>cotx = 0</u>
- x = π/2 + πn
- In the interval [0, 2π] we have π/2 and 3π/2
2. <u>cosx = 1</u>
- x = 0 + 2πn
- In the given interval we have 0 and 2π
<u>So the solution set is:</u>
Answer:
(3, -8)
Step-by-step explanation:
-3*3 - 3y = 15
-9 -3y = 15
3y = -24
y = -8
