<h2>
Explanation:</h2>
The nth term of an arithmetic series (
) and the sum of an arithmetic series (Sum), for n terms, can be found as:
![a_{n}=a_{1}+d(n-1) \\ \\ Sum=\frac{n}{2}[2a_{1}+(n-1)d] \\ \\ \\ Where: \\ \\ a_{1}:First \ term \\ \\ d:Common \ difference \\ \\ n=Number \ of \ term](https://tex.z-dn.net/?f=a_%7Bn%7D%3Da_%7B1%7D%2Bd%28n-1%29%20%5C%5C%20%5C%5C%20Sum%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a_%7B1%7D%2B%28n-1%29d%5D%20%5C%5C%20%5C%5C%20%5C%5C%20Where%3A%20%5C%5C%20%5C%5C%20a_%7B1%7D%3AFirst%20%5C%20term%20%5C%5C%20%5C%5C%20d%3ACommon%20%5C%20difference%20%5C%5C%20%5C%5C%20n%3DNumber%20%5C%20of%20%5C%20term)
So, in this exercise:
![a_{1}=a=9 \\ \\ d=4 \\ \\ n=16 \\ \\ \\ Sum=\frac{16}{2}[2(9)+(16-1)4] \\ \\ Sum=8[18+(15)4] \\ \\ Sum=8[18+60] \\ \\ Sum=8[78] \\ \\ \boxed{Sum=624}](https://tex.z-dn.net/?f=a_%7B1%7D%3Da%3D9%20%5C%5C%20%5C%5C%20d%3D4%20%5C%5C%20%5C%5C%20n%3D16%20%5C%5C%20%5C%5C%20%5C%5C%20Sum%3D%5Cfrac%7B16%7D%7B2%7D%5B2%289%29%2B%2816-1%294%5D%20%5C%5C%20%5C%5C%20Sum%3D8%5B18%2B%2815%294%5D%20%20%5C%5C%20%5C%5C%20Sum%3D8%5B18%2B60%5D%20%5C%5C%20%5C%5C%20Sum%3D8%5B78%5D%20%5C%5C%20%5C%5C%20%5Cboxed%7BSum%3D624%7D)
<h2>Learn more:</h2>
Missing numbers in triomino: brainly.com/question/10510270
#LearnWithBrainly
The friction force exerted on the 2400kg car is 9408 Newtons
<h3>
What force will be exerted on the 2400kg car?</h3>
First, we know that the friction force and mass are represented by a proportional relation, this means that we can write:
F = k*M
Where F is the force, M is the mass and k is the constant of proportionality.
We know that for a 1600kg car, a force of 6272N is exerted, replacing that we get:
6272N = k*1600kg
Solving for k we get:
k = (6272N)/(1600 kg) = 3.92 N/kg
Then the proportional relationship is:
F = (3.92 N/kg)*M
So if M = 2400kg, we have:
F = (3.92 N/kg)*2400kg = 9408 N
So the friction force exerted on the 2400kg car is 9408 Newtons
If you want to learn more about proportional realtions:
brainly.com/question/12242745
#SPJ1
Answer:
Multiply both sides by 2:
Divide both sides by 4:
Multiply both sides by 5:
