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kolezko [41]
2 years ago
15

Tell whether the angles are complementary or supplementary. Then find the value of x

Mathematics
2 answers:
lara31 [8.8K]2 years ago
8 0

Answer:

Complementary, x is 78

Step-by-step explanation:

Let's first define what complementary and supplementary angles are. Complementary angles add up to 90 degrees, and supplementary add up to 180. From this image, we can see that this is a right angle. Right angles add up to 90 degrees, therefore, this is a complementary angle.

Now, because we know that it is 90 degrees and that (x-8)+(20) = 90, then we can solve for x. However, if the angle is unknown, then we would do x-8=20. In this case, sense we know for sure this angle is complementary, we do

(x-8)+(20) = 90

X+12=90 We combined like terms

X=78 Inverse operations

You can plug 78 into x and check to see if it is correct if they are 90 degrees total.

luda_lava [24]2 years ago
3 0

Answer:

Complementary, x=78

Step-by-step explanation:

90= (x-8)+20

complementary angles add up to 90 degrees.

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In Δ A B C, the measure of the largest angle is 32 less than 3 times the smallest angle. The measure of the middle angle is 8 mo
AlladinOne [14]

Answer:

52degrees

Step-by-step explanation:

Let the measure of the largest angle be x

middle angle be y

smallest angle be z

Since the sum of angle in a triangle is 180 degrees, hence;

x + y + z = 180 .... 1

If the measure of the largest angle is 32 less than 3 times the smallest angle, then;

x = 3z - 32

3z = x+ 32

z = x+32/3 ..... 2

If he measure of the middle angle is 8 more than half the measure of the largest angle, then;

y = x/2 + 8 .... 3

Substitute 2 and 3 into 1;

x + x/2 + 8 + (x+32)/3 = 180

multiply through by 6

6x + 3x + 48 + 2(x+32) = 1080

9x + 48 + 2x + 64 = 1080

11x + 112 = 1080

11x = 1080-112

11x = 968

x = 968/11

x = 88 degrees

Get the middle angle y;

Since y = x/2 + 8

y = 88/2 + 8

y = 44 + 8

y = 52 degrees

Hence the measure of the middle angle is 52degrees

5 0
3 years ago
7+3 to the second power+(12-8) divided by 2x 4 is
cupoosta [38]

\bf \stackrel{\mathbb{P~E~M~D~A~S}}{7+3^2+(12-8)\div 2\times 4}\implies 7+3^2+(\stackrel{\downarrow }{4})\div 2\times 4\implies 7+\stackrel{\downarrow }{9}+(4)\div 2\times 4 \\\\\\ 7+9+\stackrel{\downarrow }{2}\times 4\implies 7+9+\stackrel{\downarrow }{8}\implies \stackrel{\downarrow }{16}+8\implies 24

5 0
3 years ago
How many quarts of pure antifreeze must be added to 8 quarts of a 40% antifreeze solution to obtain a 60% antifreeze solution
anyanavicka [17]

Let <em>q</em> be the number of quarts of pure antifreeze that needs to be added to get the desired solution.

8 quarts of 40% solution contains 0.40 × 8 = 3.2 quarts of antifreeze.

The new solution would have a total volume of 8 + <em>q</em> quarts, and it would contain a total amount of 3.2 + <em>q</em> quarts of antifreeze. You want to end up with a concentration of 60% antifreeze, which means

(3.2 + <em>q</em>) / (8 + <em>q</em>) = 0.60

Solve for <em>q</em> :

3.2 + <em>q</em> = 0.60 (8 + <em>q</em>)

3.2 + <em>q</em> = 4.8 + 0.6<em>q</em>

0.4<em>q</em> = 1.6

<em>q</em> = 4

4 0
2 years ago
Work out the surface area of this cylinder.<br> Radius-7 cm<br> Height-12 cm
RideAnS [48]

Answer:

226pi

Step-by-step explanation:

2 * pi * 7 *(7+12)

4 0
2 years ago
Read 2 more answers
Select all the conditions for which it is possible to construct a triangle. (7.G.1.2) Group of answer choices a. A triangle with
saw5 [17]

Answer:

  b, d, e, f

Step-by-step explanation:

Here are the applicable restrictions:

  • The sum of angles in a triangle is 180°, no more, no less.
  • The sum of the lengths of the two shortest sides exceeds the longest side.
  • When two sides and the angle opposite the shortest is given, the sine of the given angle must be at most the ratio of the shortest to longest sides.

a. A triangle with angle measures 60°, 80°, and 80° (angle sum ≠ 180°, not OK)

b. A triangle with side lengths 4 cm, 5 cm, and 6 cm (4+5 > 6, OK)

c. A triangle with side lengths 4 cm, 5 cm, and 15 cm (4+5 < 15, not OK)

d. A triangle with side lengths 4 cm, 5 cm, and a 50° angle across from the 4 cm side (sin(50°) ≈ 0.766 < 4/5, OK)

e. A triangle with angle measures 30° and 60°, and an included 3 cm side length (OK)

f. A triangle with angle measures 60°, 20°, and 100° (angle sum = 180°, OK)

_____

<em>Additional comment</em>

In choice "e", two angles and the side between them are specified. As long as the sum of the two angles is less than 180°, a triangle can be formed. The length of the side is immaterial with respect to whether a triangle can be made.

__

The congruence postulates for triangles are ...

  SSS, SAS, ASA, AAS, and HL

These essentially tell you the side and angle specifications necessary to define <em>a singular triangle</em>. As we discussed above, the triangle inequality puts limits on the side lengths specified in SSS. The angle sum theorem puts limits on the angles when only two are specified (ASA, AAS).

In terms of sides and angles, the HL postulate is equivalent to an SSA theorem, where the angle is 90°. In that case, the angle is opposite the longest side (H). In general, SSA will specify a singular triangle when the angle is opposite the <em>longest</em> specified side, regardless of that angle's measure. However, when the angle is opposite the <em>shortest</em> specified side, the above-described ratio restriction holds. If the sine of the angle is <em>less than</em> the ratio of sides, then <em>two possible triangles are specified</em>.

4 0
2 years ago
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