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3 years ago

9

Ramos went to a pizza shop and spent half of his money on lunch. If Ramos had $4.50 left after lunch, how much money did he have

originally?
I WILL GIVE BRAINLIEST!!!

1 answer:

blondinia [14]3 years ago

7 0

The Answer is $9.00 because if you just add 4.50 to 4.50 it is $9:00.

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I am stuck on this question<br> Work out :<br> 5x 3/4

brilliants [131]

Okay so to figure out this problem you need to say 5/1 times 3/4 which equals 15/4 We know that we cant have an improper fraction so we divide this and it equals 3

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3 years ago

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PLEASE HELP ASAP!!

Kisachek [45]

Answer:

my answer is C $69.87

Step-by-step explanation:

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Use yours formula to find the missing number of faces edges 15 vertices 9

Alexandra [31]

Using Euler's Formula, the number of faces is given by: 8.

<h3>What does Euler's Formula states?</h3>

It states that the number of vertices, edges and faces is related by the following equation:

V - E + F = 2.

In this problem, the parameters are given as follows:

E = 15, V = 9.

Hence the number of faces is given by:

V - E + F = 2.

9 - 15 + F = 2

F - 6 = 2

F = 8.

More can be learned about Euler's Formula at brainly.com/question/12943884

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2 years ago

D+7/−3=4<br> What is d?<br> Thanks!

givi [52]

Answer

$\boxed {d= \frac{19}{3}}$

Solution

Simplify both sides of the equation.

$\frac{7}{3} + \frac{-7}{3}$

We are left with d = 4+ $\frac{7}{3}$

Add

$\frac{12}{3}+\frac{7}{3} =\frac{19}{3}$

Hence, d = $\frac{19}{3}$

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3 years ago

Find the sum of a finite geometric sequence from n = 1 to n = 7, using the expression −4(6)n − 1.

Verizon [17]

Answer:

<h2>-223,948</h2>

Step-by-step explanation:

The formula of a sum of terms of a gometric sequence:

$S_n=a_1\cdot\dfrac{1-r^n}{1-r}$

a₁ - first term

r - common ratio

We have

$a_n=-4(6)^{n-1}$

Calculate a₁. Put n = 1:

$a_1=-4(6)^{1-1}=-4(6)^0=-4(1)=-4$

Calculate the common ratio:

$r=\dfrac{a_{n+1}}{a_n}\\\\a_{n+1}=-4(6)^{n+1-1}=-4(6)^n\\\\r=\dfrac{-4(6)^n}{-4(6)^{n-1}}=6^n:6^{n-1}\\\\\text{use}\ a^n:a^m=a^{n-m}\\\\r=6^{n-(n-1)}=6^{n-n+1}=6^1=6$

$\text{Substitute}\ a_1=-4,\ n=7,\ r=6:\\\\S_7=-4\cdot\dfrac{1-6^7}{1-6}=-4\cdot\dfrac{1-279936}{-5}=-4\cdot\dfrac{-279935}{-5}=(-4)(55987)\\\\S_7=-223948$

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3 years ago