Answer:
90 degrees
Step-by-step explanation:
Exactly right down to the last step, but some errors in combining terms.
(6m^5 + 3 – m^3 – 4m) – (–m^5 + 2m^3 – 4m + 6)
= (6m^5 + 3 – m^3 – 4m) + (m^5 – 2m^3 + 4m – 6)
= 6m^5 + 3 + (–m^3) + (–4m) + m^5 + (–2m^3) + 4m + (–6)
= [6m^5 + m^5] + [3 + (–6)] + [(–m^3) + (–2m^3)] + [(–4m) + 4m]
= (6+1)m^5 +(-1-2)m^3 +(-4+4)m +(3-6)
= 7m^5 – 3m^3 – 3
Answer:
Step-by-step explanation:
Step-by-step explanation:
In Figure 5.9 below
ABCD is a parallelogram
with m(∠ABC) = 43o
CD
. A
line through A meets
at E and m(∠AED) = 68o
a. m(∠ADE)
.
Find
b. m(∠ DAE)
c. m(∠BCD)
Answer:
thanks.
Step-by-step explanation:
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